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nignag [31]
1 year ago
5

A crystal of potassium permanganate is placed in a beaker of water. The purple colour of potassium permanganate gradually spread

s throughout the water by diffusion Explain, using the kinetic particle theory, how this process occurs.
​
Chemistry
1 answer:
cricket20 [7]1 year ago
6 0

When the crystals of potassium permanganate are preserved in water, the purple-coloured crystals of potassium permanganate break further into smaller particles that populate the distance between the molecules of water imparting a purple colour to the water. This is an example of diffusion.

<h3>What are the two conclusions given out in the method of diffusion?</h3>

Diffusion is the process of movement of solvent from higher concentration to lower concentration through a semipermeable membrane. So, we can form the decision that it cannot occur through a thick membrane from which small molecules cannot pass through.

<h3>What is difference between osmosis and diffusion?</h3>

Osmosis is the direction of solvent particles from a solution that is diluted to a more concentrated one. In contrast, diffusion is the movement of particles from a higher concentration region to a part of lower concentration.

To learn more about potassium permanganate, refer

brainly.com/question/24204185

#SPJ9

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Why is sugar soluble in water while oil cannot form a solution?​
Viefleur [7K]

Answer:

the water and alcohol interact, which means the water doesn't even dissolve the sugar or color as well as it normally would. Oil molecules are not polar so they cannot dissolve either the coloring or the sugar.

Explanation:

4 0
3 years ago
Read 2 more answers
Calculate the energy (in J/atom) for vacancy formation in silver, given that the equilibrium number of vacancies at 800 C is 3.6
MAXImum [283]

Answer:

the energy vacancies for formation in silver is \mathbf{Q_v = 3.069*10^{-4} \ J/atom}

Explanation:

Given that:

the equilibrium  number of vacancies at 800 °C

i.e T = 800°C     is  3.6 x 10¹⁷ cm3

Atomic weight of sliver = 107.9 g/mol

Density of silver = 9.5 g/cm³

Let's first determine the number of atoms in silver

Let silver be represented by N

SO;

N =  \dfrac{N_A* \rho _{Ag}}{A_{Ag}}

where ;

N_A = avogadro's number = 6.023*10^{23} \ atoms/mol

\rho _{Ag} = Density of silver = 9.5 g/cm³

A_{Ag} = Atomic weight of sliver = 107.9 g/mol

N =  \dfrac{(6.023*10^{23} \ atoms/mol)*( 9.5 \ g/cm^3)}{(107.9 \ g/mol)}

N = 5.30 × 10²⁸ atoms/m³

However;

The equation for equilibrium number of vacancies can be represented by the equation:

N_v = N \ e^{^{-\dfrac{Q_v}{KT}}

From above; Considering the  natural logarithm on both sides; we have:

In \ N_v =In N - \dfrac{Q_v}{KT}

Making Q_v the subject of the formula; we have:

{Q_v =  - {KT}   In( \dfrac{ \ N_v }{ N})

where;

K = Boltzmann constant = 8.62 × 10⁻⁵ eV/atom .K

Temperature T = 800 °C = (800+ 273) K = 1073 K

Q _v =-( 8.62*10^{-5} \ eV/atom.K * 1073 \ K) \ In( \dfrac{3.6*10^{17}}{5.3 0*10^{28}})

\mathbf{Q_v = 2.38 \ eV/atom}

Where;

1 eV = 1.602176565 × 10⁻¹⁹ J

Then

Q_v =  (2.38 \ * 1.602176565 * 10^{-19} ) J/atom  }

\mathbf{Q_v = 3.069*10^{-4} \ J/atom}

Thus, the energy vacancies for formation in silver is \mathbf{Q_v = 3.069*10^{-4} \ J/atom}

8 0
3 years ago
The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol.
alexira [117]
<span>the balanced chemical equation for the reaction is as follows;
 C</span>₃H₈ + 5O₂ ---> 3CO₂ + 4H₂<span>O
                   
stoichiometry of </span> C₃H₈ to O₂ is 1:5
   
number of moles of  C₃H₈ reacted - 0.025 g / 44.1 g/mol = 0.000567 mol according to molar ratio of 1:5
number of O₂ moles required are 5 times the amount of  C₃H₈ moles reacted therefore number of O₂ moles required - 0.000567 x 5 = 0.00284 mol .
mass of O₂ required - 0.00284 mol x 32.00 g/mol = 0.091 mol .
 answer is 0.091 mol
5 0
3 years ago
Read 2 more answers
I need help solving this for chemistry. Don’t know where to start:/
Juli2301 [7.4K]
1 electron has charge =1.602* 10⁻¹⁹ C
1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol

One ion Co²⁺   takes 2e⁻ to become Co⁰.
1 mol of Co²⁺  ions take 2 mole of e⁻ to become Co⁰, so
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9.64*10⁴(C/1mol) *0.60 (mol)≈ 5.8 *10⁴ Coulombs.
Correct answer is C
8 0
3 years ago
Help How many atoms of hydrogen(gas) form if 10 grams of aluminum react? 2Al + 6HCl = 2AlCl3 + 3H2
arlik [135]

Answer: 3.35x10²³atoms H2

Explanation: solution attached:

Convert mass of Al to moles

Do the mole to mole ratio between Al and H2

Convert moles of H2 to atoms using Avogadro's number.

4 0
3 years ago
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