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nikitadnepr [17]
3 years ago
12

Which statement describes potential energy? A. energy of motion B. stored energy C. energy due to heat D. used energy

Chemistry
2 answers:
Brrunno [24]3 years ago
8 0

A. Energy of motion describes potential energy

Inessa [10]3 years ago
7 0

B is the answer.

potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

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Calculate the mass of chloroform that contains 1.00X10^12 molecules of chloroform
Brums [2.3K]

<span>Molar mass of chloroform (CHCl3)
C = 1 * 12 = 12 a.m.u
H = 1 * 1 = 1 a.m.u
Cl = 3 * 35.5 = 106.5 a.m.u
 Molar Mass (CHCl3) = 12 + 1 + 106.5 = 119.5 g / mol
 
Knowing that: The value of Avogadro's constant corresponds to approximately </span>6,02*10^{23} molecules, if chloroform contains 1,00 * 10^{12} molecules. <span> 
We have:
 
</span>1,00 * 10^{12} * 6,02 * 10^{23} = 6,02 * 10 ^ {35} molecules<span>
 
Now, how many grams are there in the chloroform molecule?

grams -------- molecules</span><span>
119,5 </span>→ 6,02 * 10^{23}
x → 6,02 * 10^{35}

6,02 * 10 ^ {23} * x = 119,5 * 6,02 * 10 ^{35}
6,02 * 10 ^ {23}x = 719,39 * 10^{35}
x =  \frac{719,39}{6,02}*10^{35-23}
\boxed{x = 119,5*10^{12}grams}
7 0
2 years ago
I'll give 50 pts and brainliest
e-lub [12.9K]

Answer:

Response is below

Explanation:

The different types of mining are underground, surface, placer, and in-situ. Underground mining uses various materials to excavate resources from beneath the surface of the Earth. Surface mining is a category of mining that in which soil and rock overlying the mineral deposit are removed. Placer mining is the mining of stream bed deposits for minerals. In-situ mining is a mining process used to recover minerals such as copper and uranium through boreholes drilled into a deposit.

3 0
3 years ago
How many mol of C7H16 would you have if you have 76.36 grams? Give your answer to 2 decimal spaces.
tensa zangetsu [6.8K]

0.761 mol of C_7H_{16}  would you have if you have 76.36 grams.

<h3>What is a mole?</h3>

A mole is defined as 6.02214076 × 10^{23}of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Mass=76.36 grams

Moles = \frac{mass}{molar \;mass}

Moles = \frac{76.36 grams}{100.21 g/mol}

Moles = 0.761

Hence,  0.761 mol of  C_7H_{16} would you have if you have 76.36 grams.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

7 0
2 years ago
Which term is same for one mole of oxygen gas and one mole of water
miv72 [106K]
The number of atoms in one mole is same in both which is 6 x 10^23 ^23 means power 23
6 0
3 years ago
A sample was prepared by mixing 18. ml of 3.00 x 10^-3 m crystal violet (cv) with 2.00 ml of 0.250 m naoh. calculate the resulti
Aleks [24]

Answer : The resulting concentrations of CV and NaOH are 0.0027 M and 0.025 M respectively.

Explanation :

Step 1 : Find moles of crystal violet and NaOH.

The molarity formula is

Molarity = \frac{mol}{L}

Molarity of crystal violet = 3.00 \times 10^{-3} = \frac{mol (CrystalViolet)}{L}

The volume of crystal violet solution is 18 mL which is 0.018 L.

Moles of crystal violet = 3.00 \times 10^{-3} \times 0.018 = 5.4 \times 10^{-5}

Moles of crystal violet = 5.4 x 10⁻⁵

Moles of NaOH = Molarity \times L = 0.250 \times 0.00200 = 5.00 \times 10^{-4}

Moles of NaOH = 5.00 x 10⁻⁴

Step 2 : Find total volume of the solution

The total volume of the solution after mixing NaOH and crystal violet is

0.018 L + 0.00200 = 0.020 L

Step 3 : Use molarity formula to find final concentrations

Molarity of crystal violet = \frac{mol(CrystalViolet)}{Total Volume(L) } = \frac{5.4 \times 10^{-5}}{0.020} = 2.7 \times 10^{-3}

Final concentration of CV = 0.0027 M

Molarity of NaOH= \frac{mol(NaOH)}{Total Volume(L) } = \frac{5.00 \times 10^{-4}}{0.020} = 0.025 \times 10^{-3}

NaOH is a strong base and dissociates completely as follows.

NaOH (aq) \rightarrow Na^{+} (aq) + OH^{-} (aq)

The mole ratio of NaOH and OH⁻ is 1:1 . Therefore the concentration of OH⁻ is same as that of NaOH.

Concentration of OH⁻ = 0.025 M

8 0
3 years ago
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