Question

25. 00 ml of a buffer solution contains 0. 500 m hclo and 0. 380 m naclo. if 50. 00 ml of water is added to the buffer, what are the new concentrations of hclo and naclo?

Answer 1

The new concentrations of $HClO$ and $NaClO$ are  0.25M and 19M

Calculation of number of moles of each component,

Molarity of $HClO$ = number of moles/volume in lit =  0. 500 M

Number of moles = molarity  of $HClO$× volume in lit = 0. 500 M× 0.025 L

Number of moles of $HClO$ = 0.0125 mole

Molarity of $NaClO$  = number of moles/volume in lit =  0. 38 M

Number of moles = molarity of $NaClO$ × volume in lit = 0. 38 M× 0.025 L

Number of moles of  $NaClO$  = 0.95 mole

Calculation of new concentration at volume 50 ml ( 0.05L)

Molarity of $HClO$ = number of moles/volume in lit = 0.0125 mole/0.05L

Molarity of $HClO$ = 0.25M

Molarity of $NaClO$  = number of moles/volume in lit = 0.95mole/0.05L

Molarity of $NaClO$  = 19 M

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