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olganol [36]
3 years ago
8

A 32.4 L gas sample at STP is compressed to a volume of 28.4 L, and the temperature is increased to 352 K. What is the new press

ure of the gas in atmospheres
Chemistry
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

1.47 atm

Explanation:

Step 1: Given data

  • Initial volume (V₁): 32.4 L
  • Initial pressure (P₁): 1 atm (standard pressure)
  • Initial temperature (T₁): 273 K (standard temperature)
  • Final volume (V₂): 28.4 L
  • Final pressure (P₂): ?
  • Final temperature (T₂): 352 K

Step 2: Calculate the final pressure of the gas

We can calculate the final pressure of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

P₂ = P₁ × V₁ × T₂ / T₁ × V₂

P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm

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Answer:

The answer to your question is 6.77 atm

Explanation:

Data

Pressure 1 = P1 = 7.5 atm

Temperature 1 = T1 = 65°C

Pressure 2 = P2 = ?

Temperature 2 = T2 = 32°C

Process

-Use Gay-Lussac law to solve this problem

               P1/T1 = P2/T2

-Solve for P2

               P2 = P1T2 / T1

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T1 = 65 + 273 = 338°K

T2 = 32 + 273 = 305°K

-Substitution

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-Simplification

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-Result

                P2 = 6.77 atm

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<em />

Replacing (110kJ = 110000J):

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