Answer:
[KIO₃] = 0.548 M
Explanation:
Molarity is a sort of concentration which involves moles of solute in 1L of solution.
Volume of solution 5L
Mass of solution: 587 g
Let's convert the mass to moles (mass / molar mass)
587 g / 214 g/mol = 2.74 moles
Molarity is mol/L → 2.74 mol / 5L = 0.548 M
Answer:81.6%
Explanation:
Mass of CaCO3=4.010 g
Molar mass of CaCO3= 40+12+(16×3) = 100 g/mol.
Recall: number of moles(n)= mass÷ molar mass.
n=4.010÷100 = 0.0401 mol.
Molar mass of CaCl2 = 40+71= 111 g/mol.
Number of mol of CaCl2 = 5.455÷111= 0.04914 g/mol.
Mass of CaCl2 = 0.0401 × 111 = 4.4511 g of CaCl2.
Percent by mass of CaCl2 = (4.4511÷5.455) × 100
= 0.815967 ×100 = 81.5967%
Approximately; 81.6%.
1) Balanced chemical equation
8H2S +4O2 ---> S8 + 8H2O
2) Molar ratios
8 mol H2S : 4 mol O2 : 1 mol S8
3) Convert 50.0 grams of H2S into moles
moles = mass in grams / molar mass
molar mass H2S = 2*1g/mol + 32.1 g/mol = 34.1 g/mol
moles = 50.0 g / 34.1 g/mol = 1.466 moles H2S
4) Convert 60.0 g of O2 into moles
molar mass O2 = 2*16g/mol = 32.0g/mol
moles = 60.0g / 32.0 g = 1.875 moles O2
5) State limiting reagent
Theoretical ratio: 8 mol H2S / 4 mol O2 = 8/4 = 2/1 = 2
Actual ratio 1.466 mol H2S / 1.875 mol O2 < 2
=> H2S is the limiting reagent (it is consumed completely whilce some O2 remains unreacted).
6) Determine the moles of S8 produced from 1.466 moles H2S
1 mol S8 / 8 mol H2S * 1.466 mol H2S = 0.18325 mol S8
7) Convert 0.18325 mol S8 to mass
mass = number of moles * molar mass
molar mass S8 = 8 mol * 32.1g/mol = 256.8 g/mol
mass = 0.18325 mol * 256.8 g/mol = 47.1 grams
Answer: 47.1 g
Answer:
since the distance between the electron and the nucleus is smaller in B than in Li, the electrostatic nuclear force of attraction experienced by B is higher than the one experienced by Li...this translates to the higher first ionization energy in B than in Li.
Explanation:
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