The empirical formula of the alcohol is C₄H₄O
To solve the question given above, we'll begin by calculating the percentage of oxygen in the compound. This can be obtained as follow:
Carbon (C) = 70.57 %
Hydrogen (H) = 5.935 %
<h3>Oxygen (O) =? </h3>
O = 100 – (C + H)
O = 100 – (70.57 + 5.935)
O = 100 – 76.505
<h3>O = 23.495%</h3>
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Carbon (C) = 70.57 %
Hydrogen (H) = 5.935 %
Oxygen (O) = 23.495%
<h3>Empirical formula =?</h3>
Divide by their molar mass
C = 70.57 / 12 = 5.881
H = 5.935 /1 = 5.935
O = 23.495 / 16 = 1.468
Divide by the smallest
C = 5.881 / 1.468 = 4
H = 5.935 / 1.468 = 4
O = 1.468 / 1.468 = 1
Therefore, the empirical formula of the alcohol is C₄H₄O
Learn more: brainly.com/question/19667938
