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Anarel [89]
3 years ago
9

For a cosine function with amplitude A=0.75 and period T=10, what is y(4)?

Physics
2 answers:
mixer [17]3 years ago
8 0
 <span>2π/T = 2π/10 = π/5 

y(x) = A sin (wx) = 0.75 sin (πx/5) 

y(4) = 0.75 sin (4π/5) = 0.4408389392... ≈ 0.441</span><span>
</span>
Ainat [17]3 years ago
8 0

Answer:

y(4) = -0.606    

Explanation:

Given that,

The amplitude of cosine function, A = 0.75

Time period, T = 10

The cosine function is given by :

y=A\ cos(\omega t)

Since, \omega=\dfrac{2\pi}{T}

y=A\ cos(\dfrac{2\pi}{T}t)  

y=0.75\ cos(\dfrac{2\pi}{10}t)      

We need to find y (4). Put t = 4 in above equation as :

y(4)=0.75\ cos(\dfrac{2\pi}{10}\times 4)  

y(4) = -0.606       

Hence, this is the required solution.

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A police car is at rest parallel to the highway and measures the speed of cars. It sends the signal with a frequency of 1200 Hz,
masha68 [24]

Answer:

a) The car was moving at a speed of 29.167\ m.s^{-1}

b) The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c) f_o=1283.33\ Hz

Explanation:

Given:

  • original frequency of the source, f=1200\ Hz
  • speed of the source, v_s=0\ m.s^{-1}
  • velocity of the obstacle car be, v_o
  • speed of sound, s=350\ m.s^{-1}
  • observed frequency, f_o=1100\ Hz

<u>Using the equation from the Doppler's effect:</u>

\frac{f_o}{f} =\frac{(s+v_o)}{(s-v_s)}

\frac{1100}{1200} =\frac{(350+v_o)}{350-0}

v_o=-29.167\ m.s^{-1}

a)

The car was moving at a speed of 29.167\ m.s^{-1}

b)

The negative sign of v_o denotes that the observer is coming towards the police car which is the source of the sound.

c)

Now when, v_s=50\ m.s^{-1}

Then, f_o=?

Using the Doppler's eq.:

\frac{f_o}{1200} =\frac{(350+(-29.167))}{(350-50)}

f_o=1283.33\ Hz

3 0
3 years ago
A car travels 20 km South, then turns and travels 30 km East? What is the total displacement?
Ne4ueva [31]

Answer:

Explanation:36.05 km

Given

First car travels r_1=20\ km South

then turns and travels r_2=30\ km east

Suppose south as negative y axis and east as positive x axis

So, r_1=-20\hat{j}

r_2=30\hat{i}

Displacement is the shortest between initial and final point

Dispalcement=r=r_1+r_2

Displacement=-20\hat{j}+30\hat{i}

Displacement=30\hat{i}-20\hat{j}

Magnitude =\sqrt{30^2+(-20)^2}

Magnitude=36.05\ km

4 0
3 years ago
The stone, which weighs 400 g, is thrown upwards at a speed of 20 m / s. Climbed to a height of 12 m. Determine: what is equal t
maxonik [38]

Given that,

Mass of the stone, m = 400 g = 0.4 kg

Initial speed, u = 20 m/s

It is climbed to a height of 12 m.

To find,

The work done by the resistance force.

Solution,

Let v is the final speed. It can be calculated by using the conservation of energy.

v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 12} \\\\v=15.33\ m/s

Work done is equal to the change in kinetic energy. It can be given as follows :

W=\dfrac{1}{2}m(v^2-u^2)\\\\=\dfrac{1}{2}\times 0.4\times (15.33^2-20^2)\\\\=-32.99\ J

So, the required work done is 32.99 J.

3 0
3 years ago
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UkoKoshka [18]

Answer:

yo queiro escribir mi hermano

7 0
3 years ago
Why does the sky change colors at sunset?
KiRa [710]

Atmospheric refraction is the deviation of light or other electromagnetic wave from a straight line as it passes through the atmosphere due to the variation in air density as a function of height. ... Refraction not only affects visible light rays, but all electromagnetic radiation, although in varying degrees.

So in short, the answer is D.

(My answer got deleted because it didnt explain which is dumb)

8 0
3 years ago
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