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Anarel [89]
3 years ago
9

For a cosine function with amplitude A=0.75 and period T=10, what is y(4)?

Physics
2 answers:
mixer [17]3 years ago
8 0
 <span>2π/T = 2π/10 = π/5 

y(x) = A sin (wx) = 0.75 sin (πx/5) 

y(4) = 0.75 sin (4π/5) = 0.4408389392... ≈ 0.441</span><span>
</span>
Ainat [17]3 years ago
8 0

Answer:

y(4) = -0.606    

Explanation:

Given that,

The amplitude of cosine function, A = 0.75

Time period, T = 10

The cosine function is given by :

y=A\ cos(\omega t)

Since, \omega=\dfrac{2\pi}{T}

y=A\ cos(\dfrac{2\pi}{T}t)  

y=0.75\ cos(\dfrac{2\pi}{10}t)      

We need to find y (4). Put t = 4 in above equation as :

y(4)=0.75\ cos(\dfrac{2\pi}{10}\times 4)  

y(4) = -0.606       

Hence, this is the required solution.

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2 Points
yulyashka [42]

The  force applied to lift the crate is 171 N

Explanation:

The lever works on the principle of equilibrium of moments, so we can write:

F_i d_i = F_o d_o

where

F_i is the  force in input

d_i is the arm of the input force

F_o is the output force

d_o is the arm of the output force

For the lever in this problem, we have:

d_i = 0.25 m

d_o = 0.19 m

F_i = 130 N (force applied)

Solving the equation for F_o, we find the force applied to lift the crate:

F_o = \frac{F_i d_i}{d_o}=\frac{(130)(0.25)}{0.19}=171 N

Learn more about levers:

brainly.com/question/5352966

#LearnwithBrainly

6 0
3 years ago
You do 45.0 joules of work and 3.00 seconds how much power do you use​
Arada [10]

Answer:

15 watt

Explanation:

Power is the rate at which work is done.

This means you divide the work done with the amount of time used to perform the work.

The formula for Power is : P = W/t  where;

W= work done in J = 45

t= time in seconds = 3 sec

P= 45/ 3 = 15 watt

8 0
3 years ago
What kind of energy is in a rock at the edge of a cliff.
soldi70 [24.7K]

Answer:

kinetic energy

Explanation:

8 0
2 years ago
you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k
alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}

→ v_{p}=150 km/h ,  v_{w}=50 km/h

→ v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11 km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is tan^{-1}\frac{50}{150}=18.4°

The direction of the velocity is 18.4° west of south

<em>You should choose airspeed 158.11 km/h at 18.4° west of south</em>

8 0
3 years ago
The unit for energy is the​
nikitadnepr [17]

Explanation:

Joule (J) is the MKS unit of energy, equal to the force of one Newton acting through one meter.

4 0
3 years ago
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