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Setler79 [48]
1 year ago
10

When a 0. 1 m aqueous solution of hydrocyanic acid, hcn, reaches equilibrium, the ph is measured to be 5. 20. using this informa

tion, calculate ka for hydrocyanic acid
Chemistry
1 answer:
Sav [38]1 year ago
7 0

When a 0. 1 m aqueous solution of hydrocyanic acid, HCN, reaches equilibrium, the ka for hydrocyanic acid is  3.969 x 10⁻¹⁰.

<h3>What is ka value?</h3>

It's the value of equilibrium constant for the dissociation of ions into a solution. The more the Ka value the more will be dissociation.

Ka = [H₃O⁺]² / [HCN] [H₃O⁺]

The pH is 5.20

-log [H₃O⁺] = 5.20

Putting antitlog both side.

The value will be 6.30 x 10⁻⁶

Ka = (6.30 x 10⁻⁶)²  / 0.1 - 6.30 x 10⁻⁶

0.1 - 6.30 x 10⁻⁶ = 0.1

Ka = 3.969 x 10⁻¹⁰

Thus, the Ka value for hydrocyanic acid is 3.969 x 10⁻¹⁰.

To learn more about ka value, refer to the link:

brainly.com/question/2796803

#SPJ4

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How many chlorine atoms are found in 8.3 moles of chlorine?
erik [133]

Answer:

5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 1 mole of the compound contains 6.023 * 10²³ atoms, 8.3 moles of the compound how many atoms does it have?

amount of atoms=\frac{8.3 moles*6.023*10^{23}atoms }{1 mole}

amount of atoms≅ 5*10²⁴ atoms

<u><em>5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.</em></u>

4 0
3 years ago
What gas law applies to aerosol cans being stored in a cool place?
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3 0
3 years ago
A 25 gram(m) metal ball is heated to 200C(delta T) with 2330 Joules(q) of energy. What is the specific heat of the metal?
Dominik [7]

Answer:

The specific heat of the metal is 0.466 \frac{J}{g*C}

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q= 2330 J
  • c= ?
  • m= 25 g
  • ΔT= 200 °C

Replacing:

2330 J= c*25 g* 200 °C

Solving:

c=\frac{2330 J}{25 g* 200 C}

c=0.466 \frac{J}{g*C}

<u><em>The specific heat of the metal is 0.466 </em></u>\frac{J}{g*C}<u><em></em></u>

6 0
3 years ago
Read 2 more answers
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