All categories

2 years ago

Why did acid make our teeth rot?

Chemistry

2 answers:

kotykmax [81]2 years ago

8 0

Explanation:

acid make our teeth rot because strong acid are corrosive

julsineya [31]2 years ago

6 0

Acid makes your teeth rot because of the toxic chemicals inside of acid.

You might be interested in

Calculate the enthalpy of formation of butane, C4H10, using the balanced chemical

melisa1 [442]

Answer:

-125.4

Explanation:

Target equation is 4C(s) + 5H2(g) = C4H10

These are the data equations for enthalpy of combustion

C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse

To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...

Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.

7 0

3 years ago

The gold foil experiment resulted in two major discoveries which were made about the structure of the atom. what were they

DanielleElmas [232]

It showed that the nucleus is positively charged, and that the atom isn't just made of electrons.

8 0

2 years ago

Where the oxygen comes from the air (21% O2 and 79% N2). If oxygen is fed from air in excess of the stoichiometric amount requir

guajiro [1.7K]

Answer:

$y_{O2} =4.3$ %

Explanation:

The ethanol combustion reaction is:

$C_{2}H_{5} OH+3O_{2}$ → $2CO_{2}+3H_{2}O$

If we had the amount (x moles) of ethanol, we would calculate the oxygen moles required:

$x*1.10(excess)*\frac{3 O_{2}moles }{etOHmole}$

Dividing the previous equation by x:

$1.10(excess)*\frac{3 O_{2}moles}{etOHmole}=3.30\frac{O_{2}moles}{etOHmole}$

We would need 3.30 oxygen moles per ethanol mole.

Then we apply the composition relation between O2 and N2 in the feed air:

$3.30(O_{2} moles)*\frac{0.79(N_{2} moles)}{0.21(O_{2} moles)}=121.414 (N_{2} moles )$

Then calculate the oxygen moles number leaving the reactor, considering that 0.85 ethanol moles react and the stoichiometry of the reaction:

$3.30(O_{2} moles)-0.85(etOHmoles)*\frac{3(O_{2} moles)}{1(etOHmoles)} =0.75O_{2} moles$

Calculate the number of moles of CO2 and water considering the same:

$0.85(etOHmoles)*\frac{3(H_{2}Omoles)}{1(etOHmoles)}=2.55(H_{2}Omoles)$

$0.85(etOHmoles)*\frac{2(CO_{2}moles)}{1(etOHmoles)}=1.7(CO_{2}moles)$

The total number of moles at the reactor output would be:

$N=1.7(CO2)+12.414(N2)+2.55(H2O)+0.75(O2)\\ N=17.414(Dry-air-moles)$

So, the oxygen mole fraction would be:

$y_{O_{2}}=\frac{0.75}{17.414}=0.0430=4.3$ %

6 0

3 years ago

Which of the following molecules contains six bonding electrons?

cestrela7 [59]

Answer:

c2h4 (etthane........

bexcuse it has 6 bond of hydrogen

8 0

2 years ago

What would you call the following chemical reaction, Zn(s) + H2O(g) – Zno (s) + H2(g)

egoroff_w [7]

I'd say it's single replacement/displacement

5 0

2 years ago