Question

How many moles of h2o are produced in neutralization when 1. 5 mole of mg(oh)2 reacts with h2so4?

Answer 1

There are 3 moles of $H_{2} O$  are produced in neutralization when 1. 5 mole of $Mg(OH)_{2}$  reacts with $H_{2} SO_{4$

The neutralization reaction between magnesium hydroxide and sulfuric acid is given as,

$Mg(OH)_{2} + H_{2} SO_{4$ → $MgSO_{4} + 2H_{2} O$

from above chemical equation , we can conclude the molar ratio = 1:2

It means two moles of water molecule is produce from one mole of magnesium hydroxide.

So, number of moles of water molecules produced from  1. 5 mole of magnesium hydroxide = 1. 5 mole× 2 = 3 moles

Therefore,  number of moles of water molecules produced from  1. 5 mole of magnesium hydroxide is 3 moles.

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