All categories

2 years ago

How many moles of h2o are produced in neutralization when 1. 5 mole of mg(oh)2 reacts with h2so4?

Chemistry

1 answer:

Firlakuza [10]2 years ago

5 0

There are 3 moles of $H_{2} O$ are produced in neutralization when 1. 5 mole of $Mg(OH)_{2}$ reacts with $H_{2} SO_{4$

The neutralization reaction between magnesium hydroxide and sulfuric acid is given as,

$Mg(OH)_{2} + H_{2} SO_{4$ → $MgSO_{4} + 2H_{2} O$

from above chemical equation , we can conclude the molar ratio = 1:2

It means two moles of water molecule is produce from one mole of magnesium hydroxide.

So, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide = 1. 5 mole× 2 = 3 moles

Therefore, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide is 3 moles.

To learn more about neutralization

brainly.com/question/27891712

#SPJ4

You might be interested in

The scatterplot shows the number of visitors at an art show in relation to admission price. What does point A on the scatterplot

Rashid [163]

Answer:

B. When the ticket price was $15, a total of 180 people visited the art show.

Explanation:

Hope this helps! :)

3 0

3 years ago

The Ksp of barium fluoride, BaF2, is 1.6 x 10-6. A solution of 5.0M NaF is added dropwise to a 2.0L solution that is 0.016 M in

Hatshy [7]

Answer:

Precipitation will occur after the concentration of fluoride ions exceeds 0.01 M.

4 mL volume of NaF must be added to cause $BaF_2$ to precipitate.

Explanation:

Concentration of barium ions = $[Ba^{2+}]=0.016 M$

Volume of barium ion solution = 2.0 L

$BaF_2\rightleftharpoons Ba^{2+}+2F^-$

The solubility product of the barium fluoride = $K_{sp}=1.6\times 10^{-6}$

$K_{sp}=[Ba^{2+}][F^-]^2$

$1.6\times 10^{-6}=[0.016 M]\times [F^-]^2$

$[F^-]=0.01 M$

Precipitation will occur after the concentration of fluoride ions exceeds 0.01 M.

Concentration of fluoride ion = $C_1=0.01 M$

Volume of solution = $V_1=2.0 L$

Concentration of NaF solution added = $C_2=5.0 M$

Volume of NaF solution added = $V_2=?$

$C_1V_1=C_2V_2$

$V_2=\frac{0.01 M\times 2.0 L}{5.0 M}=0.004L$

1 L = 1000 mL

0.004 L = 0.004 × 1000 mL = 4 mL

4 mL volume of NaF must be added to cause $BaF_2$ to precipitate.

3 0

3 years ago

5. The prefox Semi-Deans Capardy SC Based on your knowledge of the properties of elements, which kind of elements is most likely

Nady [450]

Isn’t this app cool people are willing to help

3 0

4 years ago

What is the number of electron and neutron protons in atom 35?

Fittoniya [83]

The mass number = protons + neutrons. Bromine has a mass number of 80 and 35 protons so 80-35 = 45 neutrons. b) How many electrons does the neutral atom of bromine have? The neutral atom of bromine has 35 electrons because the number of electrons equals the number of protons.

6 0

3 years ago

Explain why Earth and other planets were not solid when they formed during the beginning of the Precambrian, approximately 4,600

Crazy boy [7]

The beginning of the Pre Cambrian is known as the Hadean eon. The planet was just born, and it was very very hot, and in fact molten. There were a lot of volcanic activities, and because of the way the solar system was created, there were still a lot of collisions between different bodies

3 0

4 years ago