How many moles of h2o are produced in neutralization when 1. 5 mole of mg(oh)2 reacts with h2so4?
1 answer:
There are 3 moles of are produced in neutralization when 1. 5 mole of
reacts with
The neutralization reaction between magnesium hydroxide and sulfuric acid is given as,
→
from above chemical equation , we can conclude the molar ratio = 1:2
It means two moles of water molecule is produce from one mole of magnesium hydroxide.
So, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide = 1. 5 mole× 2 = 3 moles
Therefore, number of moles of water molecules produced from 1. 5 mole of magnesium hydroxide is 3 moles.
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Answer: The bond between boron and hydrogen in boron trihydride is covalent bond.
Explanation:
The type of bonding between the atoms forming a compound is determined by using the electronegativity difference between the atoms. According to the pauling's electronegativity rule:
- If
, then the bond is non-polar.
- If
, then the bond will be covalent.
- If
, then the bond will be ionic.
We are given:
Electronegativity for boron = 2.0
Electronegativity for hydrogen = 2.1
As, is less than 1.7 and not equal to 0. Hence, the bond between boron and hydrogen is covalent bond.
When NAD becomes NADH, it is being reduced and gaining chemical energy.
Nicotinamide adenine dinucleotide (NAD), a coenzyme, can exist in two forms, NAD⁺ (oxidized) and NADH (reduced form).
Electrons and protons released in catabolism reactions are attached to NAD⁺. The conversion of NAD⁺ to NADH is important reaction for production of ATP during the cellular respiration.
Reduction is lowering oxidation number because element, ion or compound gain electrons.
Chemical equation for reaction of reduction of NAD⁺ (see picture below):
NAD⁺ + 2e⁻ + H⁺ → NADH
Nicotinamide adenine dinucleotide (NAD) is made of two nucleosides joined by pyrophosphate.
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