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suter [353]
2 years ago
15

How many moles of h2o are produced in neutralization when 1. 5 mole of mg(oh)2 reacts with h2so4?

Chemistry
1 answer:
Firlakuza [10]2 years ago
5 0

There are 3 moles of H_{2} O  are produced in neutralization when 1. 5 mole of Mg(OH)_{2}  reacts with H_{2} SO_{4

The neutralization reaction between magnesium hydroxide and sulfuric acid is given as,

Mg(OH)_{2}  +  H_{2} SO_{4 → MgSO_{4} + 2H_{2} O

from above chemical equation , we can conclude the molar ratio = 1:2

It means two moles of water molecule is produce from one mole of magnesium hydroxide.

So, number of moles of water molecules produced from  1. 5 mole of magnesium hydroxide = 1. 5 mole× 2 = 3 moles

Therefore,  number of moles of water molecules produced from  1. 5 mole of magnesium hydroxide is 3 moles.

To learn more about neutralization

brainly.com/question/27891712

#SPJ4

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BRAINLIESTTT ASAP! PLEASE ANSWER IN YOUR OWN WORDS. :)
const2013 [10]

Answer:

The atomic structure of an atom involves 3 subatomic particles: the proton, neutron, and electron. The proton has a positive charge and is found in the core of the atom, with the neutral neutrons that also have a mass of 1 amu (atomic mass unit) just like the proton. The nucleus is the core of the atom and contains protons and neutrons and is practically the only area with mass. The electron cloud is basically an area surrounding the nucleus and it contains negative charged electrons. Electrons have no mass but are charged with a negative charge that keeps them. I really hope this helps :)

Explanation:

There is a helpful video that actually explains the structure of an atom in a rather fun way in just 2 minutes. It really does help big time and it's kinda funny if you look it up on YT and watch:

WKRP: Venus Explains the Atom

Have a wonderful great day :)

8 0
3 years ago
Calculate the molality of 75.0 grams of MgCl2 (molar mass=95.21 g/mol) dissolved in 500.0 g of solvent.
nordsb [41]

<u>Answer:</u> The molality of magnesium chloride is 1.58 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (magnesium chloride) = 75.0

M_{solute} = Molar mass of solute (magnesium chloride) = 95.21 g/mol  

W_{solvent} = Mass of solvent = 500.0 g

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m

Hence, the molality of magnesium chloride is 1.58 m

5 0
3 years ago
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liraira [26]

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3 years ago
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Makovka662 [10]

Answer:

K = 0.5

Explanation:

Based on the reaction:

PCl₃ + Cl₂ ⇄ PCl₅

The equilibrium constant, K, is defined as:

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<em>Where P represent the pressure at the equilibrium for each one of the gases involved in the equilibrium.</em>

<em />

As:

P PCl₅ = 1.0atm

P PCl₃ = 1.0atm

P Cl₂ = 2.0atm

K = 1.0atm / 1.0atm * 2.0atm

<h3>K = 0.5</h3>
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lisov135 [29]
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