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erik [133]
3 years ago
6

What is the ph of an aqueous solution with a hydrogen ion concentration of [h ] = 9.7 × 10–4 m?

Chemistry
1 answer:
Sveta_85 [38]3 years ago
5 0
 it would be 2.51*10^-6 M
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How many liters of carbon dioxide will be produced when 89.5 L of ethane are burned? (One mole of any gas occupies 22.4 L under
yan [13]

Answer:

179 L of CO2

Explanation:

Given the equation of the reaction;

C2H6(g) + 7/2 O2(g) -------> 2CO2(g) + 3H2O(g)

Now 1 mole of ethane yields 2 moles of CO2 from the balanced reaction equation

1 mole of a gas occupies 22.4 L volume so,

22.4 L of ethane yields 44.8 L of CO2

89.5 L of ethane yields 89.5 * 44.8/22.4 = 179 L of CO2

4 0
2 years ago
Lewis dot structure for SeO
padilas [110]

Answer:

selenium dioxide

Explanation:

8 0
3 years ago
Deposition?
Soloha48 [4]

The correct term for each statement is as follows;

  • Caves being formed by acid rain dissolving underground limestone - weathering
  • Deltas forming at the mouths of rivers - deposition
  • Glaciers scraping rocks across the earth’s surface - erosion
  • Rocks being made smooth by tumbling across a stream bed - weathering
  • Ponds filling up with sediment and becoming marshes - deposition

<h3>What is weathering?</h3>

Weathering in geology is the mechanical or chemical breaking down of rocks in situ by weather or other causes. options 7 and 14 are the case in this scenario as there is a breakdown of limestone and rocks.

Erosion is the result of having been worn away or eroded, as by a glacier on rock or the sea on a cliff face. Agents of erosion are water, ice or wind. Options 12 is an example of erosion because glaciers are wearing off rocks.

Deposition is the laying down of sediment carried by wind, flowing water, the sea or ice. Sediment can be transported as pebbles, sand and mud, or as salts dissolved in water. Options 8 and 15 are examples of deposition.

Learn more about weathering and deposition at: brainly.com/question/367069

#SPJ1

8 0
1 year ago
State two essential conditions for rusting of iron. List two methods of protecting iron from rusting?​
gizmo_the_mogwai [7]
Conditions for rusting
• moisture
•oxygen

Prevention
•Painting
• Galvanisation
• Making Alloys
• greasing
Hope this helps you ;)(:

8 0
3 years ago
Consider the following reaction between mercury(II) chloride and oxalate ion.
Alina [70]

<u>Answer:</u> The rate law of the reaction is \text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)

Rate law expression for the reaction:

\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b

where,

a = order with respect to HgCl_2

b = order with respect to C_2O_4^{2-}

Expression for rate law for first observation:

3.2\times 10^{-5}=k(0.164)^a(0.15)^b  ....(1)

Expression for rate law for second observation:

2.9\times 10^{-4}=k(0.164)^a(0.45)^b  ....(2)

Expression for rate law for third observation:

1.4\times 10^{-4}=k(0.082)^a(0.45)^b  ....(3)

Expression for rate law for fourth observation:

4.8\times 10^{-5}=k(0.246)^a(0.15)^b  ....(4)  

Dividing 2 from 1, we get:

\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2

Dividing 2 from 3, we get:

\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2

3 0
3 years ago
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