Answer:
The compound a is 1-methyl cyclohexene (see attachment for structure).
Explanation:
The reaction of 1-Bromo-1-methylcyclohexane with sodium methoxide is a <u>second-order reaction</u> since the <u>methoxide ion is a strong base</u> and also a strong nucleophile. This ion attacks the alkyl halide faster than the alkyl halide can ionize to produce a first-order reaction. However, we can not see the product of nucleophilic substitution. The SN₂ mechanism is blocked due to the <u>impediment of the 1-Bromo-1-methylcyclohexane</u>. The main product, according to the Zaitsev rule, is the 1-methyl cyclohexene, thus forming a <u>double bond</u>.
Then, this cyclohexene is hydrogenated to form the cyclohexane.
D: After they emit light, electrons are sucked into the nucleus of the atom.
Answer: a = 2 ; f = 5 ; b = 2 ; g = 2 ; c = 2 ; h = 2 ; d = 4 ; i = 5 ; e = 3 ; j = 7
Explanation: Some rules to follow while calculating sig figs is
1. If a number like 4500 is present, only two sig figs are counted, but none of the zeros are, but if 4500. has a decimal point present, then you should count all the numbers available.
2. If a number like .0005 is present, only count 5 as a sig fig, however if the number is .00050, count the 0 after the 5 in this example (this would then have two sig figs.
Answer:
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