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3 years ago

Help me, I’m failing chem

2 answers:

7 0

Trick for the future:
When finding H+ or OH- from pH or pOH, all you need to type into your calculator is:
2nd log - (pH or pOH) to get the answer
For this problem, you would do 2nd log -(3.4) to get an answer of 3.98 x 10 ^ -4 ≈ 4.0 x 10 ^ -4 like the person above said

ladessa [460]3 years ago

5 0

Answer:

Explanation:

[H3O+] = 10-pH = 10-3.4 ≅ 3.981 x 10^-4 moles/liter

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A sample of sugar (C12H22O11) contains

Mariana [72]

Answer:

0.25 mol

Explanation:

Use the formula n=N/NA

n= number of mols

N = number of particles

Nᵃ = Avogadros constant = 6.02 x $\\10^{23$

So, n= $\frac{1.505 X 10^{23} }{6.02 X 10^{23}}$

The 10 to the power of 23 cancels out and you are left with 1.505/6.02, which is approximately 1/4. This is the same as 0.25 mol.

Hope this helped :)

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4 years ago

In your own words right a definition of earth core

Rasek [7]

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3 years ago

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The most condensed state of matter is A. solid B. liquid C. gas D. plasma

algol [13]

The most condensed state of matter is A. Solid Matter

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4 years ago

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What is the molality of the resulting solution when 15.0 g of Licl is combined with 105 g of water? 0/1 point 0 1.42 m 2.95 m 3.

xenn [34]

Answer:

3.37 m

Explanation:

Number of moles of solute present in 1 kg of solvent is termed as molality

It is represented by 'm'.

Thus,

$Molality\ (m)=\frac {Moles\ of\ the\ solute}{Mass\ of\ the\ solvent\ (kg)}$

Given that:

The mass of LiCl = 15.0 g

Molar mass of LiCl = 42.394 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{15.0\ g}{42.394\ g/mol}$

$Moles= 0.3538\ mol$

Mass of the solvent = 105 g

Also, 1 g = 0.001 g

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$Molality\ (m)=\frac {0.3538}{0.105}\ m$

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3 years ago

Show your work. Write a balanced net ionic equation for the following reaction. H3PO4(aq) + Ca(OH)2(aq) Ca3(PO4)2(aq) + H2O(l)

viktelen [127]

To do a balancing to result to a balanced equation, we do elemental balance from each side of the equation. Hence we do separate balances for H, P, O and Ca. In this case, the final balanced equation after balancing elementally is 3 Ca(OH)2(aq) + 2 H3Po4(aq) = 6 H2O(l) + Ca3(Po4)2(s)

6 0

4 years ago

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