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2 years ago

Find tan 0 if csc 0 = -√5/2 is in the third quadrant. A. 1/2 B.-2 C.-1/2 D. 2

Mathematics

1 answer:

MakcuM [25]2 years ago

4 0

Answer:

D. 2

Step-by-step explanation:

soh cah toa rule

sine equals opposite over hypotenuse,

cosine equals adjacent over hypotenuse, and

tangent equals opposite over adjacent

csc is 1/sin which is hypotenuse over opposite

if csc is -√5/2 then

hypotenuse is -√5

opposite is 2

3rd quadrant on a graph is bottom left

both x and y values are negative

hypotenuse means its a triangle

pythagorean theorem

a^2 + b^2 = c^2

a^2 + 2^2 = (-√5)^2

a^2 + 4 = 5

a = 1 = adjacent

tangent equals opposite over adjacent

tan is 2 / 1 which is 2

third quadrant means it's still positive

because tan is positive in quadrant 3

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3 years ago

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Answer:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
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Left to Right

Equality Properties

Trigonometry

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

Step 1: Define

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Step-by-step explanation:

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$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

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