Answer:
The answer to your question is 25.2 g of acetic acid.
Explanation:
Data
[Acetic acid] = 0.839 M
Volume = 0.5 L
Molecular weight = 60.05 g/mol
Process
1.- Calculate the number of moles of acetic acid
Molarity = moles / volume
-Solve for moles
moles = Molarity x volume
-Substitution
moles = (0.839)(0.5)
-Result
moles = 0.4195
2.- Calculate the mass of acetic acid using proportions and cross multiplications
60.05 g ----------------------- 1 mol
x ----------------------- 0.4195 moles
x = (0.4195 x 60.05) / 1
x = 25.19 g
3.- Conclusion
25.2 g are needed to prepare 0.500 L of Acetic acid 0.839M
C. The mass of an atom is greater than the combined masses of an atom's protons and electrons.
Existence of a neutron is predicted by Rutherford in 1920. So he explained difference between an atomic mass and an atomic number.
Answer:
identical atom in which an electron moves from the first to the third shell.
Atoms may occupy different energy states. The energy states are discrete, i.e. they occur at specific values only. Therefore an atom can only move to a new energy level if it absorbs or emits an amount of energy that exactly corresponds to the difference between two energy levels.
The lowest possible energy level that the atom can occupy is called the ground state. This is the energy state that would be considered normal for the atom.
An excited state is an energy level of an atom, ion, or molecule in which an electron is at a higher energy level than its ground state.
An electron is normally in its ground state, the lowest energy state available. After absorbing energy, it may jump from the ground state to a higher energy level, called an excited state.
Answer:
When the transfer of electrons occurs, an electrostatic attraction between the two ions of opposite charge takes place and an ionic bond is formed. A salt such as sodium chloride (NaCl) is a good example of a molecule with ionic bonding
Answer:
The answer to your question is C = 1.116 J/g°C
Explanation:
Data
Q = 400 J
mass = 5.6 g
Temperature 1 = T1 = 23°C
Temperature 2 = T2 = 87°C
Specific heat = C = ?
Formula
Q = mC(T2 - T1)
- Solve for C
C = Q / m(T2 - T1)
- Substitution
C = 400 / 5.6 (87 - 23)
- Simplification
C = 400 / 5.6(64)
C = 400 / 358.4
- Result
C = 1.116 J/g°C
