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NeTakaya
2 years ago
11

Driving cars lowers the ph of the oceans by what?

Chemistry
2 answers:
Hatshy [7]2 years ago
4 0

Answer: Ocean acidification

Explanation:

Driving cars can lower the pH of ocean by release of carbon dioxide in the environment. The release of carbon dioxide in the environment gets diffused in the water and increases the pH of water.

The carbon dioxide gets dissolved in water and forms carbonic acid which is harmful for the aquatic animals as it degrades their shells and can kill aquatic animals.

hence, the answer is ocean acidification.

grin007 [14]2 years ago
3 0
<span>A. releassing Co2 that dissolves and forms acid in the oceans</span>
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Read the following summary, which describes a body process. Then, answer the question.
Maksim231197 [3]

Answer:

Respiritation

Explanation:

Its Respiration because the process of breathing is known as respiration and also read the paragraph hhhhhhhhhhhhhhhhhhhhhhhh

7 0
2 years ago
What is the complete ionic equation for H2SO4(aq) + Cal2(aq) -&gt; CaSO4(s) + 2HI(aq)?
eimsori [14]
2H(+) + SO4(2-) + Ca(2+) + 2I(-) -> CaSO4(s) + 2H(+) + 2I(-)
The signs in brackets are the subscripts for the charge of the ion. This is the complete ionic equation. The net ionic equation is:
Ca(2+) + SO4(2-) -> CaSO4
6 0
3 years ago
Read 2 more answers
3.95 g of sugar (C6H12O6) is dissolved in water to make 158 mL of solution. Find the molarity.
12345 [234]

Answer:

[C₆H₁₂O₆] = 0.139 M

Explanation:

Molarity si defined as a sort of concentration. It indicates the moles of solute that are contained in 1 L of solution.

We can also say, that molarity are the mmoles of solute contained in 1 mL of solution.

For this case, the solute is sugar (glucose). Let's determine M (mmol/mL)

(3.95 g . 1mol / 180g) . (1000 mmol / 1mol) / 158 mL

We determine moles, we convert them to mmoles, we divide by mL

M = 0.139 M

Moles = 3.95 g . 1mol / 180g → 0.0219 mol

We convert mL to L → 158 mL . 1L/1000mL = 0.158L

M = 0.0219 mol / 0.158L = 0.139 M

8 0
3 years ago
We identify nucleic acid strand orientation on the basis of important chemical functional groups. These are the _________ group
zloy xaker [14]

Answer:

We identify nucleic acid strand orientation on the basis of important chemical functional groups. These are the <u>phosphate</u> group attached to the 5' carbon atom of the sugar portion of a nucleotide and the <u>hydroxyl</u> group attached to the <u>3'</u> carbon atom

Explanation:

Nucleic acids are polymers formed by a phosphate group, a sugar (ribose in RNA and deoxyribose in DNA) and a nitrogenous base. In the chain, the phosphate groups are linked to the 5'-carbon and 3'-carbon of the ribose (or deoxyribose) and the nitrogenous base is linked to the 2-carbon. Based on this structure, the nucleic acid chain orientation is identified as the 5'-end (the free phosphate group linked to 5'-carbon of the sugar) and the 3'-end (the free hydroxyl group in the sugar in 3' position).

3 0
3 years ago
What is the correct electron configuration for an element with 5 electrons in
Harlamova29_29 [7]

Answer:

it is c

Explanation:

5 0
3 years ago
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