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snow_lady [41]
3 years ago
13

Según las propiedades de una sustancia: punto de fusión (PF): 0° C, punto de ebullición (PE) de 28° C. ¿Cual es el estado de agr

egación de esta, si se encuentra a una temperatura ambiente de 30° C?
Chemistry
1 answer:
Xelga [282]3 years ago
4 0

Answer:

eeeeeeeeeeeeeeee

Explanation:

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A balloon is launched when the temperature is 15 oC and the pressure is 0.918 atm. Its volume is 11.1 L. It rises in the air unt
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Answer:

The new volume is 7,606.96 Liter.

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas in the balloon = 0.918 atm

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V_1 = initial volume of gas in the balloon = 11.1 L

V_2 = final volume of gas in the balloon = ?

T_1 = initial temperature of gas in the balloon = 15^oC=273+15=288K

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Now put all the given values in the above equation, we get:

\frac{0.918 atm\times 11.1 L}{288 K}=\frac{0.0012 atm\times V_2}{258 K}

V_2=\frac{0.918 atm\times 11.1 L\times 258 K}{288 K\times 0.0012 atm}

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Why river Ganga does not dry during summer
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