Answer:
HCl for acid, NaOH for base.
Explanation:
Acids start with H.
Bases end with OH.
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1. Remember (sum of products) - (sum of reactants)
So ΔHrxn = 2 ΔHf [H2(g)] + ΔHf [Ca(OH)2(s)] - 2 ΔHf [H2O(l)] - ΔHf [Ca(s)]
= 2*0 + -986.09 kJ/mol - 2*(-285.8 kJ/mol) - 0
Do the math and you'll have the answer. BTW the ΔHf [H2(g)] and ΔHf
[Ca(s)] were 0 because these are elements in their standard states.
</span>HOPE THIS HELPS ;)
Chlorine atom has 17 electrons. It<span> has seven </span>valence electrons<span>. These seven electrons make </span>chlorine<span> a very reactive element. A </span>valence electron<span> is an </span>electron<span> that is associated with an atom, and that can participate in the formation of a chemical bond. Hope this helps.</span>
Firstly, we need to convert 3g aspartame into moles aspartame. In order to do this we have to find the molecular mass of aspartame (the total weight of each atom of the molecule combined. This figure can be used to construct a conversion factor so that the grams may be converted into moles. Molecular weights for each atom can be found on any periodic table. Avagadro's number (6.022*10^23) is a constant value that expresses the number of molecules in one mole of a substance.
The molecular weight for aspartame is 294.3 grams per mole.
The process of finding how many atoms of H there are in 3.00g of aspartame would be like this:
1. 3g * 1mol/294.3g = .01mol aspartame (this is converting grams to moles)
2. .01mol * 6.022*10^23 = 6.022*10^21 (This is finding the number of molecules)
3. (6.022*10^21) * 18 = 1.08*10^23
This 3rd calculation is done because in part 2, you calculated the number of molecules of aspartame there were in 3g. In each molecule of aspartame there are 18 hydrogen atoms. So the final answer is:
1.08*10^23 hydrogen atoms.
Can you please elaborate?
