First, recognize that this is an elimination reaction in which hydroxide must leave and a double bond must form in its place. It is likely an E2 reaction. Here is an efficient mechanism:
1) Pre-reaction: Protonate the -OH to make it a good leaving group, water. H2SO4 or any strong H+ donor works. The water is positively charged but still connected to the compound.
2) E2: Use a sterically hindered base, such as tert-butoxide (tButO-) to abstract the hydrogen from the secondary carbon. [You want a sterically hindered base because a strong, non-sterically hindered base could also abstract a hydrogen from one of the two methyl groups on the tertiary carbon, and that leads to unwanted products, which is not efficient]. As the proton of hydrogen is abstracted, water leaves at the same time, creating an intermediate tertiary carbocation, and the 2 electrons in the C-H bond immediately are used to make a double bond towards the partial positive charge.
In the products we see the major product and water, as expected. Even though you have an intermediate, remember that an E2 mechanism technically happens in one step after -OH protonation.
Option A is correct answer.
According to octet rule, atoms have tendency to lose, gain and share electrons to complete its octet i.e. eight valence electrons are surrounded to the atom.
Since, sulphur contains six valence electrons and two chlorine atoms are present in the reaction having seven valence electrons. Thus, to complete their octet, chlorine shares a pair of electrons with the sulphur atom.
Where is the table? I dont know what to classify
The answer would be D. because when an acid and base mix the start to cancel each other out causing it to neutralize
The element is Sodium with an atomic number of 11 and electrovalent bonding takes place when it comes near an atom having seven valence electrons.
<h3>What is Electrovalent bonding?</h3>
This is also referred to as ionic bonding and involves the transfer of atoms of an element to another.
In order for both of them to achieve a stable octet configuration, sodium donates one atom to the element seven valence electrons.
Read more about Electrovalent bonding here brainly.com/question/1979431
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