Answer:
0.0831 moles of NaOH were in the original mixture
Explanation:
The strontium hydroxide, Sr(OH)2, requires 2 moles of HCl per mole of hydroxide to be neutralized.
The sodium hydroxide, NaOH, requires 1 mol of HCl per mol of hydroxide.
To solve this question we must write 2 equations:
<em>(1) </em>0.19mol = X + Y
<em>Where X = Moles NaOH; Y = Moles Sr(OH)2</em>
The moles of HCl required are:
0.100L * (2.969mol / L) = 0.2969 moles HCl
0.2969 mol = X + 2Y<em>(2)</em>
Replacing (1) in (2):
0.19mol - Y = X
0.2969 mol = (0.19mol - Y) + 2Y
0.1069mol = Y
Moles X = Moles NaOH:
0.19mol = X + 0.1069mol
X = 0.0831 moles of NaOH were in the original mixture
Answer:
B. ΔG > 0, Q > K
Explanation:
For reverse reaction to take place Q should be greater than K
Since reverse reaction should be spontaneous, forward reaction should be non spontaneous.
So, for forward reaction, ΔG > 0
Hence, the correct answer is B
Answer:
pH 8.89
Explanation:
English Translation
If the MgCl₂ solution of 0.2 M has its pH raised by adding NH₄OH, the precipitate will begin to form at a pH of approximately.
Given the solubility product (Ksp) of Mg(OH)₂ = 1.2 x 10⁻¹¹
Assuming all of the salts involved all ionize completely
MgCl₂ ionizes to give Mg²⁺ and Cl⁻
MgCl₂ ⇌ Mg²⁺ + 2Cl⁻
1 mole of MgCl₂ gives 1 moles of Mg²⁺
Since the concentration of Mg²⁺ is the same as that of MgCl₂ = 0.2 M
Mg(OH)₂ is formed from 1 stoichiometric mole of Mg²⁺ and 2 stoichiometric moles of OH⁻
Ksp Mg(OH)₂ = [Mg²⁺][OH⁻]²
(1.2 x 10⁻¹¹) = 0.2 × [OH⁻]²
[OH⁻]² = (6×10⁻¹¹)
[OH⁻] = √(6×10⁻¹¹)
[OH⁻] = 0.000007746 M
p(OH) = - log [OH⁻] = - log (0.000007746)
pOH = 5.11
pH + pOH = 14
pH = 14 - pOH = 14 - 5.11 = 8.89
Hope this Helps!!!
Answer:
It releases nutrients which causes rapid growth of planktons which leads to oxygen deficiency leading to death of aquatic animals,a phenomenon known as eutrophication.
Explanation:
Given :
A compound has a molar mass of 129 g/mol .
Empirical formula of compound is C₂H₅N .
To Find :
The molecular formula of the compound.
Solution :
Empirical mass of compound :
Now, n-factor is :
Multiplying each atom in the formula by 3 , we get :
Molecular Formula, C₆H₁₅N₃
