The most common pairing would be sodium forming an ion after transfering an electron to chlorine
For all question, all you need to use is the mole-mole ratio.
a) 25 moles C2H6O (3 moles O2/ 1 mol C2H6O)= 75 moles O2
b) 30 moles O2 (1 moles C2H6O/ 3 moles O2)= 10 moles C2H6O
c) 23 moles CO2 (3 moles O2/ 2 moles CO2) = 34.5 moles O2
d) 41 moles H2O ( 1 moles C2H6O/ 3 moles H2O= 13.7 moles C2H6O
I only got 50 points (which is not 100). :-)
Look at the graph. At 80 °C, about 38 g of solute is able to dissolve, and that’s for ever 100 g of water. That means that for every 150 grams of water, 57 grams of solute can dissolve (38/2 = 19 + 38 = 57 g) at 80 °C. Since 57 g is greater than 55 g, all for he sodium chloride should dissolve in 150 g of water at 80 °C - you can put all of that into a “mathematical explanation”.
Answer: I believe it would be using group input to discuss and prepare preliminary designs
Explanation:
