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inna [77]
2 years ago
6

PLS HELP!

Chemistry
1 answer:
Nadya [2.5K]2 years ago
6 0

Question 1

Fe(III) forms a chelate complex with salicylic acid which has purple color. therefore, when a solution is made either with salicylic acid or with aspirin having trae amount of salicylic acid in it, we see color formation in solution due to the resulting complex formed.

Question 2

The Fe(III) itself absorbs some light and gives an absorbance value for the solution. Therefore, it is necessary to blank the spectrophotometer with a Fe(III) solution prior to measurement of test solutions.

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What is the mass of an original 5.60-gram sample of iron-53 that remains unchanged after 25.53 minutes?
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Answer is 0.7 g

Reason: Given: mass of Fe = 5.60 gWe know that, half life of Fe-53 = t1/2 (Fe-53) = 8.51 min.
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The isotope 'Sr has a half-life of 28.8 years. What is the activity, measured in atoms/second, of a 50 mg sample of "Sr? (10 pts
sleet_krkn [62]

Answer:

The activity of 50mg of Sr is 2.63x10^{11} atoms/second

Explanation:

Every nuclear disintegration follows the first order rate, thus the half-life (t1/2) is t_{1/2} =\frac{Ln 2}{k} where k is the constant of the reaction.

<em>Considering 1 year equals 3.15x107 seconds</em>

\frac{28.8year x.3.15x10^{7}s }{1 year} = 9.072x10^{8} s

For Sr with t1/2 = 9.072x10^{8} s , the constant of the reaction is

k =\frac{Ln 2}{t_{1/2}}=\frac{Ln 2}{9.072x10^{8} s } = 7.64x10^{-10} s^{-1}

The activity (A) of a nucleus is A = k.N where N is the number of nucleus. Sr molecular mass is 87.6g/mol and every mol contains 6.023x1023 atoms, thus

\frac{50x10^{-3}g x 6.022x10^{23} atoms}{87.6g} = 3.44x10^{20} atoms

Therefore, the activity of 50mg of Sr is

A = k.N = 7.64x10^{-10} s^{-1} x 3.44x10^{20}atoms = 2.63x10^{11} atoms/second

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