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3 years ago

What is the oxidation number for iodine in Mg(IO3)2 ?

Chemistry

2 answers:

Leviafan [203]3 years ago

8 0

<u>Answer:</u> The oxidation state of iodine atom in the given compound is +5.

<u>Explanation:</u>

Oxidation state is the number that is assigned to an element when it gains or looses electrons. If an element gains electron, it will attain a negative oxidation state and if the element looses electrons, it will attain a positive oxidation state.

For the given chemical compound: $Mg(IO_3)_2$

We take the oxidation state of iodine atom be 'x'

Oxidation state of magnesium atom = +2

Oxidation state of oxygen atom = -2

Evaluating the oxidation state of iodine atom:

$+2+2x+6(-2)=0\\\\x=+5$

Hence, the oxidation state of iodine atom in the given compound is +5.

mestny [16]3 years ago

6 0

The oxidation number of iodine is 5 in Mg(IO3)2 which can be calculated as
Mg(IO3)2
MgI2O6
As we know that
Mg has +2
O has -2
So,
(+2) + 2I + 6 (-2)=0
2 + 2I - 12 =0
10+ 2I =0
10 = 2I
I =5

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3 years ago

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Elena-2011 [213]

Answer:

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Explanation:

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η: is the number of moles of hydrogen

n: is the number of hydrogen atoms

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Hence, the number of hydrogen atoms is:

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I hope it helps you!

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