Answer: 0.745 g of 
will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and 
is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require=
of
Mass of 
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate
Here are a few examples :)
iodine (I2)
naphthalene
aresenic (As)
ferrocene
water (H2O)
carbon dioxide (CO2)
Hope this helps :)
Answer:
1.1 × 10⁻⁴ M
Explanation:
Let's consider the following double displacement reaction.
CuCl₂(aq) + 2 AgNO₃(aq) → 2 AgCl(s)+ Cu(NO₃)₂(aq)
We can establish the following relations:
- The molar mass of AgCl is 143.32 g/mol.
- The molar ratio of AgCl to CuCl₂ is 2:1
The moles of CuCl₂ that reacted to produce 7.7 mg of AgCl are:
The molarity of CuCl₂ is:
The answer to the problem is 100
Answer: The excess amount changes from a gas into a liquid or solid (ice). The process of water changing from a gas to a liquid is called "condensation," and when gas changes directly into a solid, it is called "deposition." These two processes are how clouds form.
