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bezimeni [28]
3 years ago
7

What is pomsis? can someone please help ​

Chemistry
1 answer:
Feliz [49]3 years ago
8 0
Yeah man I can help explain a little bit fits
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Which description gives the steps for creating hydroelectric power
Inessa05 [86]

Answer:

The answer to your problem is

B) river water stored in a reservoir flows down a channel in a dam, turning a turbine as it passes. the turbine is connected to a generator that produces electricity, and then the water continues downstream

plz can i get brainliest

Explanation:

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3 years ago
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Which of these characteristics best describes a basic solution?
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Short Answer:  <span>Solutions of dilute, weak acids - the only kind that you might taste - are sour. Weak, dilute bases are bitter. Solutions of bases are slippery.

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3 years ago
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If 500 mL of liquid mercury weighs 6.53 kg, what is the mass in pounds? A) 1.44 lb B) 2960 lb C ) 14.4 lb D) 7.19 lb E) 2.96 lb
soldi70 [24.7K]

Answer:

The correct option is: C ) 14.4 lb      

Explanation:

The standard International unit of mass is kilogram, kg. Other commonly used units of mass are grams (g), tonne (t), pounds (lb).

The mass of 500 mL liquid mercury is 6.53 kg.

Since, 1 kg = 2.20462 lb ≈ 2.205 lb

Therefore, the mass of 500 mL liquid mercury in pounds = 6.53 × 2.20462 = 14.39619 lb ≈ 14.4 lb.  

8 0
3 years ago
(3.6 x 104) / (4 x 10-6)
Feliz [49]

Answer:

930 pls mark me branilest

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3 years ago
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Calculate the mass of oxygen gas (O2) dissolved in a 5.00 L bucket of water exposed to a pressure of 1.13 atm of air. Assume the
Ilia_Sergeevich [38]

Answer:

The mass of oxygen gas dissolved in a 5.00 L bucket of water exposed to a pressure of 1.13 atm of air is 0.04936 grams.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{gas}=K_H\times p_{gas}

where,

K_H = Henry's constant =

p_{O_2} = partial pressure of oxygen

We have :

Pressure of the air = P

Mole fraction of oxygen in air = \chi_{O_2}=0.210

p_{O_2}=P\times \chi_{O_2}

=0.210\times 1.13 atm= 0.2373 atm

K_H = Henry's constant = 1.30\times 10^{-3}M/atm

Putting values in above equation, we get:

C_{O_2}=1.30\times 10^{-3}M/atm\times 0.2373  atm\\\\C_{O_2}=0.003085 M

Moles of oxygen gas = n

Volume of water = V = 5 L

Molarity = \frac{Moles}{Volume(L)}

0.003085 M=\frac{n}{5 L}

n = 0.003085 M\times 5 L=0.001542 mol

Mass of 0.001542 moles of oxygen gas:

0.001542 mol × 32 g/mol = 0.04936 g

The mass of oxygen gas dissolved in a 5.00 L bucket of water exposed to a pressure of 1.13 atm of air is 0.04936 grams.

5 0
3 years ago
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