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abruzzese [7]
2 years ago
14

A 5 Ω and a 5 Ω resistor are in parallel. What is their total resistance?

Physics
1 answer:
Agata [3.3K]2 years ago
3 0

Answer:

B. 2.5 Ω

Explanation:

\frac{1}{5} +\frac{1}{5}=0.4

Put a one on top of the 0.4

\frac{1}{0.4} =2.5

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What is know as law of inertia? ​
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5 0
3 years ago
You have a double slit experiment, with the distance between the two slits to be 0.025 cm. A screern is 120 cm behind the double
dimulka [17.4K]

Answer:

The wavelength of the light is 633 nm.

Explanation:

Given that,

Distance between the two slits d= 0.025 cm

Distance between the screen and slits D = 120 cm

Distance between the slits y= 1.52 cm

We need to calculate the angle

Using formula of double slit

\tan\theta=\dfrac{y}{D}

Where, y = Distance between the slits

D = Distance between the screen and slits

Put the value into the formula

\tan\theta=\dfrac{1.52}{120}

\theta=\tan^{-1}\dfrac{1.52}{120}

\theta=0.725

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Using formula of wavelength

d\sin\theta=n\lambda

Put the value into the formula

0.025\times\sin0.725=5\times\lambda

\lambda=\dfrac{0.025\times10^{-2}\times\sin0.725}{5}

\lambda=6.326\times10^{-7}\ m

\lambda=633\ nm

Hence, The wavelength of the light is 633 nm.

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