For a certain interval of time, an object is acted on by a constant non-zero force. For this interval of time . . . . .
A. The object is at rest. No. From F=ma, if F is not zero, the object can't remain at rest.
<em>B.</em> <em>The object's velocity changes.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
C. The object's velocity can only increase. No. It might decrease.
D. The object is moving with constant velocity. No. From F=ma, if F is not zero, there must be acceleration.
<em>E.</em> <em>The object is accelerating.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
Hi there!
We can use the equation:
d = x₀ + vt, where:
x₀ = initial distance from the reference point
v = velocity (m/s)
t = time (sec)
Plug in the given values:
d = 248 + 5(49)
d = 493m
Particles stay the same unless there is a chemical change whether the matter is solid, liquid or gas. ... When substances change state there is no change in mass so if 100 g of ice is melted 100g of water are formed this will boil to form 100g of steam (this is called "conservation of mass").
You have to reduce 2.00 an5.00 I order to use the×that=0.800
