A ball is thrown up into the air with the initial velocity of 18 m/s. A) How high does the ball go? B) Calculate the time needed
1 answer:
Answer:
(a) h = 16.53 m (b) t = 1.83 s
Explanation:
Given that,
The initial velocity of a ball, u = 18 m/s
When it reaches to the maximum height, its final velocity v will be 0. Let it goes to a maximum height of h meters.
Finding t using first equation of motion as follows :
v = u +at
Here, a = -g and v = 0
The time needed for the ball to reach its max height is 1.83 s.
Let h is the maximum height. Using second equation of motion to find it :
So, it will go to a maximum height of 16.53 m.
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Answer:
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Explanation:
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