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AleksandrR [38]
3 years ago
5

A centripetal force causes circular motion because it accelerates an object

Physics
2 answers:
MAVERICK [17]3 years ago
6 0

The answer is option A.

Centripetal force is always directed towards the centre and does not change the speed of the body,but there is a change in the direction.

ElenaW [278]3 years ago
3 0

Answer:

Towards the center of circle, which changes the direction of motion but not speed

Explanation:

The force acting on an object when it is moving in circular path is called centripetal force. The formula for centripetal force is given by :

F=\dfrac{mv^2}{r}

Where

m = mass

v = velocity

r = radius of circle

In a circular path, the velocity of object changes continuously while its speed remains constant. The centripetal force acts towards the center of circle. Hence, the correct option is (a) " towards the center of circle, which changes the direction of motion but not speed ".                 

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Read 2 more answers
One mole of an ideal gas does 3000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 atm and
taurus [48]

Answer:

(a) Initial volume will be 7.62 L

(b) Final temperature will be 303.85 K

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We have given one mole of ideal gas done 3000 J

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Final volume V_2=25L = 0.025 m^3

Number of moles n = 1

(B) From ideal gas of equation we know that PV=nRT

So 1.01\times 10^5\times0.025=1\times 8.31\times T

T = 303.85 Kelvin

(B) For isothermal process work done is equal to

W=nRTln\frac{V_2}{V_1}

3000=1\times 8.314\times 303.85\times ln\frac{0.025}{V_1}

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\frac{0.025}{V_1}=3.2808

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3 years ago
A fan blade, initially at rest, rotates with a constant acceleration of 0.029 rad/s2. What is the time interval required for it
LenKa [72]

Answer:

The time interval is  t = 21.30 \ s

Explanation:

From the question we are told that

    The constant acceleration is \alpha  = 0.029 \ rad / s^2

    The displacement is  \theta  =  6.58 \ rad

     

According to the second equation of motion we have that

    \theta  =  w_i* t  +  \frac{1}{2} *  \alpha  t^2

given that the blade started from rest

     w_i which is the initial angular velocity is 0

 So  

       \theta  = 0 +  \frac{1}{2} *  \alpha  t^2

 =>  t = \sqrt{ \frac{2 * \theta }{\alpha } }

substituting values  

=>    t = \sqrt{ \frac{2 * 6.58 }{0.029 } }

=>    t = 21.30 \ s

6 0
3 years ago
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