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AleksandrR [38]
4 years ago
5

A centripetal force causes circular motion because it accelerates an object

Physics
2 answers:
MAVERICK [17]4 years ago
6 0

The answer is option A.

Centripetal force is always directed towards the centre and does not change the speed of the body,but there is a change in the direction.

ElenaW [278]4 years ago
3 0

Answer:

Towards the center of circle, which changes the direction of motion but not speed

Explanation:

The force acting on an object when it is moving in circular path is called centripetal force. The formula for centripetal force is given by :

F=\dfrac{mv^2}{r}

Where

m = mass

v = velocity

r = radius of circle

In a circular path, the velocity of object changes continuously while its speed remains constant. The centripetal force acts towards the center of circle. Hence, the correct option is (a) " towards the center of circle, which changes the direction of motion but not speed ".                 

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What is mass times acceleration?
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Answer:

Force

Explanation:

The mass of an object is the quantity of matter it contains. It is measured in kilograms.

Acceleration is the ratio of the change in the velocity of an object to the change in time. It is measured in m/s^{2}.

When the mass of an object is multiplied with its acceleration, this gives the average force applied on the object. As force is defined as agent that can change the state of an object.

i.e     F = m × a

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The two major classes of force are; contact force and field force.

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Explain 2 reasons why reactions take place faster at high temperature
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How might burning fossil fuels affect the composition of gases in the atmosphere?
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5 0
3 years ago
A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The ang
olga55 [171]

Answer:

9.22 s

Explanation:

One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad

Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:

For the child: s_c = \omega_ct = 0.233t

For the horse: s_h = s_0 + a_ht^2/2 = 1.57 + 0.0136t^2/2 = 1.57 + 0.0068t^2

For the child to catch up with the horse, they must cover the same angular distance within the same time t:

s_c = s_h

0.233t = 1.57 + 0.0068t^2

0.0068t^2 - 0.233t + 1.57 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{0.233\pm \sqrt{(-0.233)^2 - 4*(0.0068)*(1.57)}}{2*(0.0068)}

t= \frac{0.233\pm0.11}{0.0136}

t = 25.05 or t = 9.22

Since we are looking for the shortest time we will pick t = 9.22 s

6 0
3 years ago
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