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3 years ago

Hurry up i need help.

Physics

1 answer:

spayn [35]3 years ago

8 0

Answer:

The answer would be B) The Same

Explanation:

Not gonna lie I checked my class notes but I figured this would help :)

Good luck!!!

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A 10-foot ladder is leaning straight up against a wall when a person begins pulling the base of the ladder away from the wall at

docker41 [41]

Answer:

$y = 4.36$

Explanation:

Let the height of the ladder be L

$L = 10$

Also:

Let $x = distance\ from\ the\ base\ of\ the\ ladder$

Let $y = height\ of\ the\ base\ of\ the\ ladder$

When the ladder leans against the wall, it forms a triangle and the length of the ladder forms the hypotenuse.

So, we have:

$L^2 = x^2 + y^2$ --- Pythagoras Theorem

When the base is 9ft from the wall, this means that:

$x = 9$

Substitute 9 for x and 10 for L in $L^2 = x^2 + y^2$

$10^2 = 9^2 + y^2$

$100 = 81 + y^2$

Make $y^2$ the subject

$y^2 = 100 - 81$

$y^2 = 19$

Make y the subject

$y = \sqrt{19$

$y = 4.36$

<em>Hence, the true distance at that point is approximately 4.36ft</em>

8 0

3 years ago

Please help me out !!!!!!

nikdorinn [45]

Answer:

Explanation:

8 0

3 years ago

A current of 0.2 A flows through a conductor for 5minutes. How much charge would have passed through the conductor?

Montano1993 [528]

As we know,

$electric \: \: current = \dfrac{charge}{time}$

so, let's solve for charge (q) :

time = 5 minutes = 5 × 60 seconds = 300 seconds.

$0.2 = \dfrac{q}{300}$

$q = 300 \times 0.2$

$q = 60$

hence, the charge = 60 coulombs (C)

4 0

3 years ago

Black holes must have a mass three or more times the mass of _____.

tia_tia [17]

The answer is <span>d. the sun</span>

7 0

3 years ago

Read 2 more answers

The Orion nebula is one of the brightest diffuse nebulae in the sky (look for it in the winter, just below the three bright star

Oxana [17]

Answer:

T=183.21K

Explanation:

We have to take into account that the system is a ideal gas. Hence, we have the expression

$PV=nRT$

where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant.

Thus, it is necessary to calculate n and V

V is the volume of a sphere

$V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi (5.9*10^{15}m)^3=8.602*10^{47}m^3$

V=8.86*10^{50}L

and for n

$n=\frac{(4000M_s)/(2*mH)}{6.022*10^{23}mol^{-1}}=3.95*10^{36}mol$

Hence, we have (1 Pa = 9.85*10^{-9}atm)

$T=\frac{PV}{nR}=\frac{(6.8*10^{-9}*9.85*10^{-6}atm)(8.86*10^{50}L)}{(0.0820\frac{atm*L}{mol*K})(3.95*10^{36}mol)}\\\\T=183.21K$

hope this helps!!

8 0

3 years ago