All categories

1 year ago

When an electron in a quantum system drops from a higher energy level to a lower one, the system __

1 answer:

4 0

When an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.

The energy of the electron drops when it transitions levels, as well as the atom releases photons. The emission of the photon occurs as the electron transitions from an energy state to a lower state. The photon energy represents precisely the energy that would be lost when an electron moves to a level with less energy.

When such an excited electron transitions from one energy level to another, this could emit a photon. The energy drop would be equivalent to the power of the photon that is released. In electron volts, the energy of an electron, as well as its associated photon (emitted or absorbed) has been stated.

Therefore, when an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.

To know more about electron

brainly.com/question/1255220

#SPJ4

You might be interested in

PLEASE HELP ME!!!! ILL FIND A WAY TO GET YOU 100 POINTS!!!

Umnica [9.8K]

It’s c had this problem last week

8 0

3 years ago

A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl

diamong [38]

Answer:

$\large \boxed{\text{98 m$\cdot$s}^{-2}}$

Explanation:

The formula for the velocity of the ball is

$v = \sqrt{2gh}$

1. Velocity at time of impact

$v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}$

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

$v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}$

3. Acceleration

$a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}$

5 0

3 years ago

Determine the number of protons and neutrons in an atom of Uranium - 238

Mila [183]

Answer:

146

Explanation:

uranium is 92 and the mass number of the isotope is given as a 238 therefore it is not the two protons 92 electrons and

real explanation Google it

7 0

2 years ago

When electrolyzing copper (ll) chloride, what reaction takes place at the anode? What reaction takes place at the cathode?

klemol [59]

Answer:

Copper ions are reduced into copper atoms.

Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎

Explanation:

During electrolysis, the positive H⁺ and Cu⁺ ions move to the negative cathode and negative OH⁻ and Cl⁻ ions move to the positive anode.

At cathode, copper ions are preferentially discharged due to the low electromotive force required to discharge them compared to the hydrogen ion. The copper ions gain the two electrons lost by the chloride ions when the are discharged. (2 Cl⁻₍aq₎ → Cl₂₍g₎ + 2e⁻)

Thus the half equation is as follows:

Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎

5 0

3 years ago

The transition metals are located in what block of the periodic table

gladu [14]

Located in the D block

7 0

2 years ago