It would be C
2 kg x 1000 g/kg x 1mol/18.02 x 6.03 kj/mol = 669kj
Hey there !
Number of moles of solution: 4.3 moles
Volume in liters:
450.0 mL / 1000 => 0.45 L
Therefore:
Molarity = number of moles / volume of solution ( L)
Molarity = 4.3 / 0.45
=> 9.55 M
Hope that helps!
Answer:
0.366 moles to the nearest thousandth.
Explanation:
The molar mass of acetic acid CH3COOH = 2*12 + 4(1.008) + 2*16
= 60.03 g so the number of moles in 22 g
= 0.366.
Answer:
4) 1.5 mol
Explanation:
Well, the equation is already balanced and the mole to mole ratio of reactants and products are all 1. So if the limiting reactant is HCl and you have 1.5 mol, you do the mole to mole ratio with NaCl and since it is 1 to 1, there'd be 1.5 mol of NaCl.
