Answer:
HOAc is stronger acid than HClO
ClO⁻ is stronger conjugate base than OAc⁻
Kb(OAc⁻) = 5.5 x 10⁻¹⁰
Kb(ClO⁻) = 3.3 x 10⁻⁷
Explanation:
Assume 0.10M HOAc => H⁺ + OAc⁻ with Ka = 1.8 x 10⁻⁵
=> [H⁺] = √Ka·[Acid] =√(1.8 x 10⁻⁵)(0.10) M = 1.3 x 10⁻³M H⁺
Assume 0.10M HClO => H⁺ + ClO⁻ with Ka = 3 x 10⁻⁸
=> [H⁺] = √(3 x 10⁻⁸)(0.10)M = 5.47 x 10⁻⁵M H⁺
HOAc delivers more H⁺ than HClO and is more acidic.
Kb = Kw/Ka, Kw = 1 x 10⁻¹⁴
Kb(OAc⁻) = 5.5 x 10⁻¹⁰
Kb(ClO⁻) = 3.3 x 10⁻⁷
a) The total pressure of the system is 1.79 atm
b) The mole fraction and partial pressure of hydrogen is 0.89 and 1.59 atm respectively
c) The mole fraction and the partial pressure of argon is 0.11 and 0.19 atm.
<h3>What is the total pressure?</h3>
We know tat we can be able to obtain the total pressure in the system by the use of the ideal gas equation. We would have from the equation;
PV = nRT
P = pressure
V = volume
n = Number of moles
R = gas constant
T = temperature
Number of moles of hydrogen = 14.2 g/2g = 7.1 moles
Number of moles of Argon = 36.7 g/40 g/mol
= 0.92 moles
Total number of moles = 7.1 moles + 0.92 moles = 8.02 moles
Then;
P = nRT/V
P = 8.02 * 0.082 * 273/100
P = 1.79 atm
Mole fraction of hydrogen = 7.1/8.02 = 0.89
Partial pressure of hydrogen = 0.89 * 1.79 atm
= 1.59 atm
Mole fraction of argon = 0.92 / 8.02
= 0.11
Partial pressure of argon = 0.11 * 1.79 atm
= 0.19 atm
Learn more about partial pressure:brainly.com/question/13199169
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If the number of rats decrease, snakes would look for another prey.
The balanced chemical equation of the reactions given is as follows:
- 2LiHCO3 -----> Li2CO3 + H2O + CO2
- 2 N2 + 5 O2 -----> 2 N2O5
- MgBr2 + KOH -----> KBr + Mg(OH)2
- Mn + 2 CuCl -----> 2 Cu + MnCl2
- 8 Zn + S8 -----> 8 ZnS
- 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
- 2 K + 2 H2O -----> 2 KOH + H2
- C5H12 + 8 O2 -----> 6H2O + 5 CO2
- 2 KOH + H2CO3 -----> 2 H2O + K2CO3
- C4H802 + 6 O2 -----> 4 H20 + 4 CO2
- 16 Al + 3 S8 ---> 8 Al2S3
<h3>How to balance chemical equations</h3>
Balancing of chemical equations is the process of adding numerical coefficients in front of moles of reactants and products to ensure that the moles of atoms of elements of the reactants is equal to the moles of atoms of products formed.
The balanced chemical equation of the reactions given is as follows:
- 2LiHCO3 -----> Li2CO3 + H2O + CO2
- 2 N2 + 5 O2 -----> 2 N2O5
- MgBr2 + KOH -----> KBr + Mg(OH)2
- Mn + 2 CuCl -----> 2 Cu + MnCl2
- 8 Zn + S8 -----> 8 ZnS
- 2 NaOH + H2SO4 -----> 2 H2O + Na2SO4
- 2 K + 2 H2O -----> 2 KOH + H2
- C5H12 + 8 O2 -----> 6H2O + 5 CO2
- 2 KOH + H2CO3 -----> 2 H2O + K2CO3
- C4H802 + 6 O2 -----> 4 H20 + 4 CO2
- 16 Al + 3 S8 ---> 8 Al2S3
Learn more about balancing of chemical equations at: brainly.com/question/15428811
