How could we separate the baking soda from the after after it had already been mixed in? helppp!!!

Be sure to answer all parts. this is a two-part question. first, draw the minor alkene product that should be formed in the reac

kotykmax [81]

Answer:

See explanation below

Explanation:

The question is incomplete, however, I found a question very similar to this, and I'm assuming this is the question you are asking to answer. If it's not, please tell me which one it is. Here's a tip for you to get an idea of how to solve.

Picture 1, would be the original question. Picture 2 is the answer of it.

Now, This is a E1 reaction where this type of reactions are taking place in two steps. The first step is the formation of the carbon cation, this step is always slow. The secon step is the addition of a nucleophyle, or, in this case, formation of a pi bond, and we get a alkene.

Hope this can help you

8 0

3 years ago

Two methods by which we can conserve water and water the plants.

Natalka [10]

Answer:

Two methods which help us to conserve water are:

Sprinkler irrigation system: this irrigation has an arrangement of vertical pipes with rotating nozzles on the top. It is more useful in the uneven and sandy land where sufficient water is not available.

Drip irrigation system: this irrigation system has an arrangement of pipes or tubes with very small holes in them to water plants drop by drop just at the base of the root. It is very efficient as water is not wasted at all.

3 0

2 years ago

Draw the structure of the compound formed from propanoic acid and dimethylamine

jeyben [28]

The compound form from propanoic acid and dimethylamine is 3-(dimethylamino)propanoic acid. Propanoic acid is a liquid carboxylic acid that has pungent and unpleasant smell resembling to body odor. Its chemical formula is C2H5C00H. Moreover, dimethylamine is an organic compound and a secondary amine that is colorless, flammable gas with an ammonia like odor. Its chemical formula is (CH3)2NH.

The 2D structure is attached here.

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7 0

3 years ago

For molecules with more than one ionizable groups, such as glycine, which of the following statements is true? For molecules wit

tester [92]

Answer: Option (a) is the correct answer.

Explanation:

The isoelectric point (pI) is actually the pH where a particular amino acid exists as a neutral molecule. This means that if pH equals pI then there will be no electric charge on the molecule.

Therefore, the statement at pH near the pI, nearly all the molecules carry no net charge, is true.

A buffer is composed of a solution of weak acid or base and salt of weak acid/base.So, when pH equals pI then there occurs no net charge. Hence, there will be no existence of conjugate acid-base pair.

Therefore, the statement when the pH is near the pI, the solution is near its maximum buffering ability, is false.

It is known that when pH is less than pI then there will be a net positive charge on the amino acid.

Hence, the statement at a pH near the pI, nearly all the molecules carry a net positive charge, is false.

When pH is greater than pI then amino acid will have a net negative charge. Hence, the statement at a pH near the pI, nearly all the molecules carry a net negative charge, is false.

Thus, we can conclude that out of the given options the statement at pH near the pI, nearly all the molecules carry no net charge, is true.

5 0

3 years ago

Which model of the Adam was modeled after the solar system

Fofino [41]

. After Rutherford's model was published, a Danish scientist named Niels Bohr became interesting in the orbits of the electrons. He was inspired by thinking of atoms as tiny Solar Systems, where the elect

5 0

3 years ago