Answer:
9, 10, 11, 12, and 13
Step-by-step explanation:
The first term is determined when n=1, therefore a(1)=1+8=9
The second term is determined when n=2, therefore a(2)=2+8=10
The third term is determined when n=3, therefore a(3)=3+8=11
The fourth term is determined when n=4, therefore a(4)=4+8=12
The fifth term is determined when n=5, therefore a(5)=5+8=13
In a triangle, the midline joining the midpoints of two sides is parallel to the third side and half as long
2(5x+2) = 3x + 32
10x + 4 = 3x + 32
10x - 3x = 32 - 4
7x = 28
x = 28/7
x = 4
The length of the midsegment = 5x+2 = 5·4 + 2 = 22
We are given displacement = 20 meters.
Time given = 4.7 seconds.
Velocity = 4.3 m/s.
Please note : Velocity is a vector quantity. A vector quantity depends on magnitude and direction as well.
We are given magnitude of displacement = 20 meter and time 4.7 seconds but the direction is missing there.
If it would be in forward direction it would be positive and if it would be in backward direction, it would be of negative.
Therefore, <u>"B)the direction"</u> is correct option.
Answer:
The common difference is same = d = -9
Therefore, the data represent a linear function.
Step-by-step explanation:
Given the table
x y
1 4
2 -5
3 -14
4 -23
5 -32
Finding the common difference between all the adjacent terms of y-values
d = -5 - 4 = -6,
d = -14 - (-5) = -14+5 = -9
d = -23 - (-14) = -23 + 14 = -9
d = -32 - (-23) = -32 + 23 = -9
It is clear that the common difference between all the adjacent terms is same.
Thus,
d = -9
We know that when y varies directly with x, the function is a linear function.
Here, it is clear that each x value varies 1 unit, and each y value varies -9 units.
i.e. The common difference is same = d = -9
Therefore, the data represent a linear function.
Answer:
D
Step-by-step explanation:
our basic Pythagorean identity is cos²(x) + sin²(x) = 1
we can derive the 2 other using the listed above.
1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)
1 + tan²(x) = sec²(x)
2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)
cot²(x) + 1 = csc²(x)
A. sin^2 theta -1= cos^2 theta
this is false
cos²(x) + sin²(x) = 1
isolating cos²(x)
cos²(x) = 1-sin²(x), not equal to sin²(x)-1
B. Sec^2 theta-tan^2 theta= -1
1 + tan²(x) = sec²(x)
sec²(x)-tan(x) = 1, not -1
false
C. -cos^2 theta-1= sin^2
cos²(x) + sin²(x) = 1
sin²(x) = 1-cos²(x), our 1 is positive not negative, so false
D. Cot^2 theta - csc^2 theta=-1
cot²(x) + 1 = csc²(x)
isolating 1
1 = csc²(x) - cot²(x)
multiplying both sides by -1
-1 = cot²(x) - csc²(x)
TRUE
