May be considered average
The initial action of the nurse should be noting the time of the day the test was done. The result would depend largely on the time of the test and the position of the client during the test.
If it was done in the morning, it shows that there is no problem with the client’s intra-ocular pressure because normal IOP in the morning is between 10-21mmHg and higher. Moreover, a flat position could also result to increase eye pressure.
Answer:
there is no right or wrong answer the teacher is wanting your opinion.
Explanation:
Rabbit's position vector (r) in the unit vector is 203.5î - 57j and the magnitude and directional angle of vector (r) are 195.35m and 0.004° respectively.
Given
x = 0.3t² + 7.2t + 28
y = 0.22t² - 9.1t +30
At t = 15s
x = 0.3(15)² + 7.2(15) +28 = 203.5
y = 0.22(15)² - 9.1(15) + 30 = -57
The rabbit's position vector (r) in unit vector notation is:
r = 203.5î - 57j
The magnitude of position vector (r)
r = √x² + y²
r = √(203.5)² - (57)² =√38163.25
= 195.35m
The directional angle of position vector (r)
tanθ = y/x = -57/203.5
θ =
(-57/203.5)
θ = 0.004°
Hence, rabbit's position vector (r) in the unit vector is 203.5î - 57j and the magnitude and directional angle of vector (r) are 195.35m and 0.004° respectively.
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