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Mazyrski [523]
2 years ago
12

Expectant parents are thrilled to hear their unborn baby's heartbeat, revealed by an ultrasonic detector that produces beeps of

audible sound in synchronization with the fetal heartbeat. Suppose the fetus's ventricular wall moves in simple harmonic motion with an amplitude of 1.80 mm and a frequency of 115 beats per minute.(a) Find the maximum linear speed of the heart wall. Suppose a source mounted on the detector in contact with the mother's abdomen produces sound at 2000000.0 Hz, which travels through tissue at 1.50 km/s .
Physics
1 answer:
Shtirlitz [24]2 years ago
3 0

If a source mounted on the detector in contact with the mother's abdomen produces sound at 2000000.0 Hz, which travels through tissue at 1.50 km/s. The maximum linear speed of the heart wall is 5 km/s.

<h3>What is linear speed?</h3>

Straight speed is the distance gone by a moving item. The speed with which the item moves in a straight way is called direct speed. In straightforward words, we can comprehend that the direct speed is a distance shrouded by a body in a given time span. The direct speed of a point on a turning object relies upon its separation from the focal point of pivot. At the point when an item goes in a round movement its direct speed is the speed digression to the circle of movement at some random point. Direct speed portrays how quick the actual item covers a given distance.

Learn more about linear speed, refer:

brainly.com/question/11001321

#SPJ4

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Three faces of a cube of side length 2 cm each have a uniform electric field of magnitude 500 N/C pointing directly inward. The
Maurinko [17]

Answer:

Q=-8.85*10^{-12}*0.36 C =-3.186*10^{-12} C

(negative charge)

Explanation:

Hi!

To solve this problem we use Gauss Law for electric fields, which relates the flux of electric field E through a closed surface S with the charge Q enclosed by that surface:

\int_{S} \vec{E}\cdot \vec{n} \;dA = \frac{Q}{\epsilon_0}

\vec{n} = \text{outwards surface normal}\\\epsilon_0 = 8.85*10^{-12}\frac{C^2}{Nm^2}

In this problem S is a cube of side length 2cm. The integral is easy because the electric field is uniform in each face, and normal to the face. The total integral is the sum of the integrals in each of the six faces.

\int_{S} \vec{E}\cdot \vec{n} \;dA = \frac{Q}{\epsilon_0} = 3(-500\frac{N}{C} (2cm)^2) + 3(200\frac{N}{C} (2cm)^2)

(-1500*4*10^{-4}\frac{Nm^2}{C} + 600*4*10^{-4}\frac{Nm^2}{C} )=-0.36\frac{Nm^2}{C}

Q=-8.85*10^{-12}*0.36 C =-3.186*10^{-12} C

3 0
3 years ago
The first elemen on the periodic table is
Naddik [55]

Answer:

Hydrogen (H)

Explanation:

If you look at the periodic table, the elements are numbered. H is number 1 which stands for Hydrogen.

5 0
3 years ago
Read 2 more answers
An airplane wing is designed to make the air move
amm1812

An airplane wing is designed to make the air move  <em>faster over the top than under the bottom. (c)</em>  They do this by making the top of the wing curved and the bottom flat, so the air that flows over the top has farther to go.

It turns out, according to a scientist named Bernoulli, that air exerts lower pressure when it moves faster. So if it moves faster over the top of the wing, then there's less pressure on the top of the wing and more on the bottom, and the wing thinks there's a force that's LIFTING it . . . <em>very convenient and useful</em> if the wing is part of an airplane !

7 0
3 years ago
I'm trying to find the potential energy of a planet using formula G M(sun) x m(planet) / r. I have given G - newton's graviation
ludmilkaskok [199]

Answer:

-5.39\times10^{33} J

Explanation:

Potential energy =

-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J

7 0
2 years ago
If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds
stepan [7]

Answer:

a) s_{max} = 96\,ft, b) v(4.449\,s) = -78.368\,\frac{ft}{s}

Explanation:

a) The maximum height is obtained with the help of the First and Second Derivative Tests:

First Derivative

v(t) = 64 - 32\cdot t

64 - 32\cdot t = 0

t = 2\,s

Second Derivative

a(t) = -32 (absolute maximum)

The maximum height reached by the ball is:

s (2\,s) = 32 + 64\cdot (2\,s) - 16\cdot (2\,s)^{2}

s_{max} = 96\,ft

b) The time required by the ball to hit the ground is:

32+64\cdot t - 16\cdot t^{2} = 0

-16\cdot (t^{2}-4\cdot t - 2) = 0

t^{2}-4\cdot t - 2 = 0

(t -4.449)\cdot (t+0.449)\approx 0

Just one root offers a solution that is physically reasonable:

t = 4.449\,s

The velocity of the ball when it hits the ground is:

v(4.449\,s) = 64 - 32\cdot (4.449\,s)

v(4.449\,s) = -78.368\,\frac{ft}{s}

6 0
3 years ago
Read 2 more answers
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