Answer:
a) a = 7.72 m / s², N = 19.9 N and b) F = 25.5 N
Explanation:
To solve this problem we will use Newton's second law, let's set a reference system with an axis parallel to the plane and gold perpendicular axis. Let's break down the weight (W)
sin52 = Wx / W
cos52 = Wy / W
Wx = W sin52
Wy = w cos 52
Let's write them equations
X axis
Wx = ma
Y Axis
N-Wy = 0
N = Wy
a) Let's calculate the acceleration
a = W sin52 / m = mg sin 52 / m
a = g sin 52
a = 9.8 sin52
a = 7.72 m / s²
The force of the ramp is normal
N = Wy = mg cos 52
N = 3.3 9.8 cos 52
N = 19.9 N
b) For the block to move at constant speed the sum of force on the axis must be zero,
F - Wx = 0
F = Wx
F = mg sin52
F = 3.3 9.8 sin 52
F = 25.5 N
Parallel to the plane and going up
B is the answer for your question the answer is b an elevator slowing down
It should be noted that the student should use K = 1/2mv² with the initial speed of the block for one trial.
<h3>
Method of using the data collected.</h3>
From the complete information, the student wants to use the data collected and the known quantities from the experiment to determine the initial total mechanical energy of the block-ramp-Earth system for all trials in the experiment.
In this case, it's important to use K = 1/2mv² with the block's initial speed for one trial due to the fact that the initial speed is the same in all the trials.
Learn more about experiments on:
brainly.com/question/17274244
NT
=
r / β
where NT is the threshold density, r is the recovery and death rate and β is the transmission coefficient.
= 0.4 / 0.2
= 2
Answer:
0.5m/s2
Explanation:
acceleration= change in velocity/time taken
= v - u/ t
= 10-5/10
=5/10
= 0.5m/s2
