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LiRa [457]
3 years ago
8

An airplane wing is designed to make the air move

Physics
1 answer:
amm18123 years ago
7 0

An airplane wing is designed to make the air move  <em>faster over the top than under the bottom. (c)</em>  They do this by making the top of the wing curved and the bottom flat, so the air that flows over the top has farther to go.

It turns out, according to a scientist named Bernoulli, that air exerts lower pressure when it moves faster. So if it moves faster over the top of the wing, then there's less pressure on the top of the wing and more on the bottom, and the wing thinks there's a force that's LIFTING it . . . <em>very convenient and useful</em> if the wing is part of an airplane !

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Fig.3 shows three 10 g particles that have been glued to a rod of length L = 6 cm and negligible mass. The assembly can rotate a
Phoenix [80]

(a) The amount of work required to change the rotational rate is 0.0112 J.

(b) The decrease in the rotational inertia when the outermost particle is removed is 64.29%.

<h3>Moment of inertia of the rod</h3>

The moment of inertia of the rod from the axis of rotation is calculated as follows;

I = md² + m(2d)² + m(3d)²

where;

  • m is mass = 10 g = 0.01 kg
  • d = 3 equal division of the length

d = 6/3 = 2 cm = 0.02 m

I = md²(1 + 2² + 3²)

I = 14md²

I = 14(0.01)(0.02)²

I = 5.6 x 10⁻⁵ kg/m³

<h3>Work done to change the rotational rate</h3>

K.E = ¹/₂Iω²

K.E = ¹/₂(5.6 x 10⁻⁵)(60 - 40)²

K.E = ¹/₂(5.6 x 10⁻⁵)(20)²

K.E = 0.0112 J

<h3>Percentage decrease of rotational inertia when the outermost particle is removed</h3>

I₂ = md² + m(2d)²

I₂ = 5md²

ΔI = 14md² - 5md²

ΔI = 9md²

η = (ΔI/I) x 100%

η = (9md²/14md²) x 100%

η = 64.29 %

Learn more about rotational inertia here: brainly.com/question/14001220

#SPJ1

4 0
2 years ago
What is the momentum of a 5 kg object that has a velocity of 1.2 m/s? 3.8 kg • m/s 4.2 kg • m/s 6.0 kg • m/s 6.2 kg • m/s
Gnesinka [82]

Answer:

Your answer will be 6.0kg•m/s

Explanation:

In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity                   = 5 * 1.2                    = 6So the momentum of the object is 6 Newton.

4 0
4 years ago
Read 2 more answers
At an amusement park, a roller coaster carrying nine homosexuals, moving at 18 m/s, jumps its track at a point that is 20 meters
Lorico [155]

It is the same if a white father and a white mother give birth to a black kid, so the mother accuses the father for having (let's say mating) with a black women.

6 0
3 years ago
A) an electron has an initial speed of 226000 m/s. if it undergoes an acceleration of 4.0 x 1014 m/s2, how long will it take to
KIM [24]

initial speed of 226000 m/s

acceleration of 4.0 x 1014 m/s2,

speed of 781000 m/s

What is Acceleration?

  • Acceleration is a rate of change of velocity with respect to time with respect to direction and speed.
  • A point or an object moving in a straight line is accelerated if it speeds up or slows down.
  • Acceleration formula can be written as,

                    a = (v - u ) / t m/s²

As we have to find the time taken, the formula can be altered as,

t = \frac{v-u}{a}

where, t - time taken to reach a final speed

v - final velocity

u - initial velocity

a - acceleration.

Substituting all the given values,

t =\frac{781000 - 226000} {4* 1014}

= 1.3875 × 10⁻⁹ seconds.

So, taken to reach the final speed is found to be 1.3 × 10⁻⁹ 8iH..

7 0
2 years ago
Explain why the amplitude of the wave did not change when you increased the frequency of the stimulation. how well did the resul
barxatty [35]
The amplitude did not change when the recurrence was expanded on the grounds that the long headstrong time of the heart forestalls adjustment. It is the most extreme removal or separation moved by a point on a vibrating body or wave measured from its balance position. It is equivalent to the one-a large portion of the length of the vibration way.
5 0
4 years ago
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