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2 years ago

A student lays down unit cubes to find the

Mathematics

1 answer:

Slav-nsk [51]2 years ago

7 0

Answer:

They may have counted the total number of cubes instead of just the length.

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The conference will begin at 8:30 a.m. and will last 5 hours 45 minutes. What time will the conference be over?

Delicious77 [7]

Add the time to the start time:

8:30

1 hour: 9:30 am

2 hours: 10:30am

3 hours: 11:30am

4 hours: 12:30pm

5 hours: 1:30pm

Then 45 minutes makes the time 2:15pm

Answer: 2:15 pm

3 0

3 years ago

Do you know how to find rate of change? X&Y intercepts? Zeros?

Rzqust [24]

#Rate of change

Rate of change is slope

If two points be (x1,y-1) and (X2,Y2) then

Slope=m=y_2-y_1/x_2-x_1

If a line be ax+by+c=0

m=-a/b

#X and y inetercept

If a equation given y=mx+b

To find x intercept put y=0
To find y inetercept put x=0

#Zeros

To find the zeros spot out the x inetercepts

The x values of the x intercepts are the zeros

3 0

3 years ago

Please help I can't work out the gradient

Annette [7]

Answer:

a is 2.5

b is 1

gradient is rise over run

8 0

4 years ago

Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.

SashulF [63]

<h3><u>Answer</u>:- </h3>

$\longrightarrow \sf \$ \: 307.2$

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

$\green{ \underline { \boxed{ \sf{Surface \: area \:of \:Cube = 6a^2}}}}$

<u>where a is side of the cube </u>

$\begin{gathered}\\\quad \sf Surface \: area \:of \:Cube = 6\times(3.2)^2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 6\times 3.2\times3.2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 61.44 cm^2 \\\end{gathered}$

Now,

$\maltese \sf Cost \:of \:painting \: 1 \: cm² = \$ 5$

$\sf Cost \: of \: painting \: 61.44 \:cm²=61.44×5$

$\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2$

$\leadsto$ Thus it would cost $ 307.2 to paint the entire cubical block.

3 0

3 years ago

In the diagram below, triangle ABC is drawn with altitude BD. If AD = 30 and AC = 36, determine the length of AB rounded to the

denis-greek [22]

9514 1404 393

Answer:

32.9

Step-by-step explanation:

The ratio of long side to hypotenuse is the same for all of the triangles in the figure.

AD/AB = AB/AC

AB^2 = AD·AC = 30·36

AB = 6√30 ≈ 32.863

To the nearest tenth, AB ≈ 32.9.

5 0

3 years ago