H(x) = 125^x
Domain: all the real numbers (from negative infinity to infinity)
Range: all the positive real numbers.
As x decreases 125^x decreases approaching to 0. The function will never reach the value 0 but will approximate to it as x goes to negative infinity. The rate of decreasing gets lower and lower, with a limit of zero, when x becomes more and more negative.
As x increases 125^x increases indefinetely and at an increasing rate. That means that the increase is accelerated (the bigger the value of x the bigger the rate of increasing).
Use this formula: A = P(1 + r/n)^nt, where A is the amount after interest (what you are solving for), P is the amount you invested originally, r is the rate at which it was invested in decimal form, n is the number of times the compounding occurs each year, t is the time in years it is invested. It would look like this: A = 500(1 + [.06/12])^12*5. Do inside the parenthesis first to get 1 + .005 = 1.005. Now raise that to the 60th power (12 times 5 is 60) to get 1.34558. Now multiply that by the 500 out front to get a total amount of $674.43
-3
because it goes left 1 up3
3/-1 = -3 as the slope
Answer:
y=3/2x+5
Step-by-step explanation:
