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nasty-shy [4]
2 years ago
15

How would you prepare a 35 ml solution of 95% (volume/volume solution of ethanol?

Chemistry
1 answer:
Artyom0805 [142]2 years ago
7 0

Explanation:

<em><u>Solutions. 1. If 47 g of KCl dissolved in enough water to give 375 mL of soloution, what is the molarity ... vo volume of solute . ... v/v ethanol, how much 95% v/v ethanol ... prepare 200. mL ...</u></em>

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Help me with this question please
mash [69]

<u>Answer:</u>

a. Oxidising agent: Cl₂

b. Reducing agent: NaBr

c. Oxidised: NaBr

d. Reduced: Cl₂

e. Oxidation numbers before reaction: Cl= 0, Na= +1, Br= -1

f. Oxidation numbers after reaction: Cl= -1, Na= +1, Br= 0

<u>Explanation:</u>

Oxidising agents reduces themselves, oxidising other elements/compounds.

Reducing agents oxidise themselves, reducing other elements/compounds.

Oxidation is the <u>loss</u> of electrons or an <u>increase</u> in oxidation number.

Reduction is the <u>gain</u> of electrons or <u>decrease</u> in oxidation number.

6 0
1 year ago
A potential energy diagram is shown. What is the activation energy of this reaction?
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50 KJ is the answer!
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2 years ago
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jasenka [17]
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4 0
3 years ago
Consider the following reactions. (Note: (s) = solid, (l) = liquid, and (g) = gas.) ½H2(g) + ½I2(g) → HI(g), ΔH = +6.2 kcal/mole
BARSIC [14]
½H2(g) + ½I2(g) → HI(g) ΔH = +6.2 kcal/mol
or...
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that is   H2SO4  = 2H^+  +  SO4^2-

According to Arrhenius  an acid  dissociate  to give H^+  ions H2SO4 is an acid  since  it dissociate  to  give  two hydrogen ions  
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