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user100 [1]
3 years ago
15

1. Increased motion in the particles in a liquid allows the particles to

Chemistry
2 answers:
docker41 [41]3 years ago
7 0

Answer:

stop their flow

Explanation:

because the weight eventually becomes equal to the drag force

bazaltina [42]3 years ago
6 0

Answer:

B is the answer of this question.

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What acids in alcohol make it evaporate
fgiga [73]

The acids found in alcohol that make it evaporate are called organic acids.

An organic acid is an organic compound that has acidic properties. There are two types: one has a carboxyl (COOH) group, and the other type has a phenol group.

The most common organic acids are those with a carboxyl group and include acetic acid, formic acid, lactic acid and all fatty acids.  Perfumes  include organic acid in their composition to make them volatile. Volatile substances evaporate easily, and this is important for perfumes. They need to dissipate easily into the surrounding environment and spread their good smell. 




6 0
4 years ago
Did Adam Jackson win by
devlian [24]

Answer:

by a number

Explanation:

4 0
3 years ago
Read 2 more answers
What is the formula of the compound formed between the potassium ion and the sulfide ion?
KIM [24]
The formula for K+ and S-2 is K2S because you need 2 potassium ions to balance out the sulfide ion
4 0
3 years ago
Bromine has two isotopes, Br79 and Br81. The isotopes occur in a 50:50 (1:1) ratio. Given that the mass spectrum of bromine cont
AlekseyPX

Answer:

There will be 3 peaks.

Relative height of the atomic peaks would be; 158, 160 and 162

Explanation:

We are told that Bromine has two isotopes namely 79Br and 81Br in a 1 : 1 ratio (50 : 50).

This means that a compound which contains 1 bromine atom will have two peaks in the molecular ion region but it depends on which bromine isotope is contained in the molecular ion.

Thus;

Relative height of atomic peaks is given by;

m/z = 79Br¯ 79Br+ = 158

79Br¯ 81Br+ = 160

81Br¯ 81Br+ = 162

7 0
3 years ago
What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su
anastassius [24]

Answer:

V=27992L=28.00m^3

Explanation:

Hello,

In this case, the combustion of methane is shown below:

CH_4+2O_2\rightarrow CO_2+2H_2O

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3

Best regards.

8 0
3 years ago
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