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liberstina [14]

3 years ago

10

All atoms of oxygen have the same mass number. True or False

2 answers:

Radda [10]3 years ago

7 0

False all atoms of oxygen do not have the same mass number.0

r-ruslan [8.4K]3 years ago

3 0

Answer:

pretty sure it's false

Explanation:

hope this helps!

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Bess [88]

Answer:

i feel like a is right i dont know but i would just guess

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6 0

3 years ago

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Please help! If a forensic chemist discovers evidence through examination which would prove a person guilty of a crime, why then

Bogdan [553]

Explanation: You cannot be convicted of a crime without evidence. You cannot be convicted of a state crime. You cannot be convicted of a federal crime. If there is no evidence against you, under the law, it simply is not possible for the prosecutor's office to obtain a conviction at trial. So, when you do have evidence it is really impossible to not get convicted unless the judge truly believes your side of the story and declares you not guilty.

I hope this helped :) If not i'm sorry!

7 0

3 years ago

Please can someone please help me !!

Anestetic [448]

Answer:

False

Explanation:

5 0

3 years ago

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Solnce55 [7]

Because nothing appeared he concluded that <span>that living things could NOT just appear or come from nonliving things like water and air</span>

3 0

4 years ago

odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add

Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

Explanation :

First we have to calculate the moles of $H_2SO_4$ .

$\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}$

Given:

Molar mass of $H_2SO_4$ = 98 g/mole

Mass of $H_2SO_4$ = $6.05\times 10^3kg=6.05\times 10^6g$

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

$\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol$

The moles of $H_2SO_4$ is, $6.17\times 10^4mol$

Now we have to calculate the moles of $Na_2CO_3$

The balanced neutralization reaction is:

$Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3$

From the balanced chemical reaction we conclude that,

As, 1 mole of $H_2SO_4$ neutralizes 1 mole of $Na_2CO_3$

So, $6.17\times 10^4mol$ of $H_2SO_4$ neutralizes

Now we have to calculate the mass of $Na_2CO_3$

$\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3$

Molar mass of $Na_2CO_3$ = 106 g/mole

$\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg$

Thus, the mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

3 0

3 years ago