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2 years ago

The kinetics of a gas phase reaction of the form A → Products results

Chemistry

1 answer:

Romashka [77]2 years ago

6 0

It will take 21.57min for the concentration of A to reach

0.080 M if The kinetics of a gas phase reaction of the form A → Products results

The kinetic concept of gases is an easy, historically tremendous classical version of the thermodynamic conduct of gases, with which many major principles of thermodynamics had been installed. gasoline kinetics is technological know-how in the department of fluid dynamics, worried with the take a look at of motion of gases and their outcomes on physical systems. based on the principles of fluid mechanics and thermodynamics, gasoline dynamics arises from the studies of fuel flows in transonic and supersonic flights.

Unit of rate constants for

0 order reaction = M/s

1st order reaction = sec-1

2nd order reaction = M-1s-1

So, this reaction is a 0-order reaction because it's rate constant has a unit M/min

Now half-life of 0 order reaction = Ao/2K

Where Ao = initial concentration

K = rate constant

using kinetics of a gas

Given,

Ao = 0.337M and K = 0.00781M/min

Putting all the values we get

t1/2 = 0.337/2×0.00781 min

On calculating

t1/2 = 21.57min

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What is the mass of 1.867 moles of the element chlorine

alekssr [168]

Answer:

66.185g

Explanation:

m= n ×MM

m= 1.867 × 35.45

m= 66.185g

8 0

4 years ago

PLZZZZ HELP MEH THANKS YEET

aleksandrvk [35]

Remark

The question with these kind of problems is "Which R do you use?" That's where dimensional analysis is so handy. You must look at the units of the givens and choose your R accordingly. You'll see how that works in a moment.

You need to list the givens along with their units and in this case the property you want to solve for. You need all that to determine the R value

Givens

n = 0.25 moles

T = 35°C = 35 + 273.15 = 308.15°K

V = 6.23 L

Pressure = P in kPa

Which R

The units of the R you want has to have units of moles, kPa, °K and liters

The R that you want is 8.314

Formula

PV = nRT

P 6.23 = 0.25 * 8.314 * 308.15 Combine the left

P*6.23 = 640.5

P = 640.5/6.23 = 102.81 The answer should be 100 kpA of 1.0 * 10^2 kPa

because the number of moles has only 2 sig digs.

But if sig digs are not a problem 102.8 is likely close enough.

Second Question

You are going to have to clean up the numbers. I think I've got only 1 chance at this. The partial pressures of the 2 gases will add up to the total pressure. So the total pressure was 100 approx and the water vapor was 3.36 kPa. The difference is

Total = air + water vapor

100.18 = air + 3.36 about Subtract 3.36 from both sides.

100.18 - 3.36 = 96.82 about. Pick the answer that is closest to that. I'll clean up the numbers if I can.

Answer C

6 0

3 years ago

Read 2 more answers

A gas occupies 1200 litres at 2 atm pressure. To what pressure must it be compressed to occupy 60 litres at the same temperature

MArishka [77]

P2 = 40 atm

Explanation:

Given: