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dusya [7]
3 years ago
6

Silver is produced as a byproduct of gold

Chemistry
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

Element Properties

atomic number 47

atomic weight 107.868

melting point 960.8 °C (1,861.4 °F)

boiling point 2,212 °C (4,014 °F)

specific gravity 10.5 (20 °C [68 °F])

oxidation states +1, +2, +3

electron configuration [Kr]4d105s1

hope that helps

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Alex787 [66]
PH= log[H3O+]
10.25=log [H3O+]
[H3O+] = 10^10.25
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6 0
3 years ago
Read 2 more answers
How many grams of carbon monoxide are needed to react with an excess of iron (III) oxide to produce 198.5 grams of iron? Fe2O3(s
erastova [34]

Answer : The grams of carbon monoxide needed are 148.89 g

Solution : Given,

Mass of iron, Fe = 198.5 g

Molar mass of iron, Fe = 56 g/mole

Molar mass of carbon monoxide, CO = 28 g/mole

First we have to calculate the moles of iron, Fe.

\text{ Moles of Fe}=\frac{\text{ Mass of Fe}}{\text{ Molar mass of Fe}}=\frac{198.5g}{56g/mole}=3.545moles

The balanced chemical reaction is,

Fe_2O_3(s)+3CO(g)\rightarrow 3CO_2(g)+2Fe(s)

From the balanced reaction, we conclude that

2 moles of iron produces from the 3 moles of carbon monoxide

3.545 moles of iron produces from the \frac{3}{2}\times 3.545=5.3175 moles of carbon monoxide

Now we have to calculate the mass of carbon monoxide, CO.

\text{ Mass of CO}=\text{ Moles of CO}\times \text{ Molar mass of CO}

\text{ Mass of CO}=(5.3175moles)\times (28g/mole)=148.89g

Therefore, the grams of carbon monoxide needed are 148.89 g

7 0
2 years ago
Given the standard entropy values in the table, what is the value of º for the following reaction?
Mandarinka [93]
Hello.

The answer is <span>+313.766 J/mol·K
</span>
 Use the coefficients of the reaction and sum the product entropies less the reactant entropies:

4*188.8 + 2*213.7 - 3*205.1 - 2* 126.8 = 313.7 J/mol*K

Have a nice day
8 0
3 years ago
How can people conserve water at home? rinsing dishes with cool water instead of warm water
Y_Kistochka [10]
By not letting the sick run while doing other things like scrubbing dishes..
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What is the percent by mass of oxygen in al2o3 ?
Snezhnost [94]
mr oxygen= 16. 16 x 3= 48
mr Al2O3= 27 + 27 + 48= 102

(48/102) X 100%= 47.05% oxygen
4 0
3 years ago
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