Question

A 36 gram sample of water has an initial temperature of 22 degrees Celsius after the sample absorbs 1200joules of heat energy the final temperature of the sample is

Answer 1

We can use the heat equation,
Q = mcΔT 

 

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

Let's assume that the finale temperature is T.

Q = 1200 J

m = 36 g
c = 4.186 J/g °C

ΔT = (T - 22) 

 

By applying the formula,

   1200 J = 36 g x 4.186 J/g °C x (T - 22)

  (T - 22) = 1200 J / (36 g x 4.186 J/g °C)

  (T - 22) = 7.96 °C

            T = (7.96 + 22) °C = 29.96 °C

            T = 30 °C 

Hence, the final temperature is 30 °C.

Answer 2

Base on the question that states to calculate the final temperature of the sample if a 36 gram sample of water has an initial temperature of 22 degrees celcius after the sample absorbs 1200 joules of heat energy, base on that, the answer would be 30 degree celcius. I hope this would help