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natima [27]
3 years ago
6

Air is composed of 79%N^2, 21% O^2. if the air pressure is 101.3 kPa, what are the pressures of N^2 and O^2

Chemistry
1 answer:
pychu [463]3 years ago
5 0
According to Dalton's law of partial pressures, a mixture of gases inflict pressure in a direct proportion to their volume/mass etc. Therefore, since 79 percent of the air is composed of nitrogen and 21 percent of Oxygen, we multiply 101.3 kPa by 0.79 = 80.027 kPa by Nitrogen, 101.3 kPa by 0.21 = 21.273 kPa by Oxygen.
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Mr. Ragusa asks Hassan to make silver crystals from the following reaction.
SVEN [57.7K]

Answer:

Percentage yield = 61.7%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

2AgNO₃ + Cu —> Cu(NO₃)₂ + 2Ag

Next, we shall determine the mass of AgNO₃ that reacted and the mass of Ag produced from the balanced equation. This is illustrated below:

Molar mass of AgNO₃ = 108 + 14 + (16×3)

= 108 + 14 + 48

= 170 g/mol

Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g

Molar mass of Ag = 108 g/mol

Mass of Ag from the balanced equation = 2 × 108 = 216 g

SUMMARY:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Next, we shall determine the theoretical yield of Ag. This can be obtained as follow:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Therefore, 51 g of AgNO₃ will react to produce = (51 × 216)/340 = 32.4 g of Ag.

Thus, the theoretical yield of Ag is 32.4 g.

Finally, we shall determine the percentage yield of Ag. This can be obtained as follow:

Actual yield = 20 g

Theoretical yield = 32.4 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 20 / 32.4 × 100

Percentage yield = 61.7%

6 0
3 years ago
Plz help all chemist!
solmaris [256]

Answer:

D. bromine

Explanation:

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K Ca Cu Br

6 0
4 years ago
The pKa of the α‑carboxyl group of serine is 2.21 , and the pKa of its α‑amino group is 9.15 . Calculate the average net charge
sleet_krkn [62]

Answer:

Net charge in serine at pH equal to 8.30 is "0"

Explanation:

  • At pH > pK_{a}, carboxyl group exists as -CO_{2}^{-} (charged)
  • At pH < pK_{a}, carboxyl group exists as -COOH (neutral)
  • At pH > pK_{a}, amino group exists as -NH_{2} (neutral)
  • At pH < pK_{a}, amino group exists as -NH_{3}^{+} (charged)
  • So, at pH = 8.30, both carboxyl and amino group exists in charged state.
  • Net charge in serine at pH equal to 8.30 is "0".
  • Structure of serine at pH equal to 8.30 has been shown below.

8 0
4 years ago
Which vein carries oxygenated blood back into the heart?
Finger [1]

Answer:

The veins that carry oxygenated bloof back into the heart are the pulmonary arteries.

Explanation:

Oxygen-rich blood flows from the lungs back into the left atrium (LA), or the left upper chamber of the heart, through four pulmonary veins. Oxygen-rich blood then flows through the mitral valve (MV) into the left ventricle (LV), or the left lower chamber.

6 0
2 years ago
Read 2 more answers
What is the concentration of H3O+ ions in saliva if [OH-] = 4.22 x 10-10 M? Provide the pH and the classification of this sample
OLEGan [10]

pH=4.625

The classification of this sample of saliva : acid

<h3>Further explanation</h3>

The water equilibrium constant (Kw) is the product of concentration

the ions:

Kw = [H₃O⁺] [OH⁻]

Kw value at 25° C = 10⁻¹⁴

It is known [OH-] =  4.22 x 10⁻¹⁰ M

then the concentration of H₃O⁺:

\tt 10^{-14}=4.22\times 10^{-10}\times [H_3O^+]\\\\(H_3O^+]=\dfrac{10^{-14}}{4.22\times 10^{-10}}=2.37\times 10^{-5}

pH=-log[H₃O⁺]\tt pH=5-log~2.37=4.625

Saliva⇒acid(pH<7)

6 0
3 years ago
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