Answer: 69.0 grams
Explanation:-
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
10 moles of require 1 mole of
Thus 0.83 require= of
Thus is the limiting reagent as it limits the formation of product.
As 10 moles of give = 4 moles of
Thus 0.83 moles of give = of
Mass of
Thus 69.0 g of will be produced from the given masses of both reactants.
Answer:
P₂ = 1312.88 atm
Explanation:
Given data:
Initial temperature = 25°C
Initial pressure = 1250 atm
Final temperature = 40°C
Final pressure = ?
Solution:
Initial temperature = 25°C (25+273.15 = 298.15 K)
Final temperature = 40°C ( 40+273.15 = 313.15 k)
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1250 atm / 298.15 K = P₂/313.15 K
P₂ = 1250 atm × 313.15 K / 298.15 K
P₂ = 391437.5 atm. K /298.15 K
P₂ = 1312.88 atm
Answer:
A) As the phase changes occur, the freedom of motion of the particles increases.
Explanation:
As the phase changes occur, the freedom of motion of the particles increases.
Its element think hope it helps