Four moles of Argon gas are at a pressure of 1.90 atm, and the temperature is 50 degrees C. What is the volume of the gas?
1 answer:
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Answer:
Ethyl propionate
Explanation:
Calculating the double bond equivalence as:
DBE = C - (H/2) - (X/2) + (N/2) +1
Where
C is the number of carbon atoms
N is the number of nitrogen atoms
X is the number of halogens
H is the number of hydrogen atoms
So, according to the formula,
DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1
It means there is one double bond or one ring.
from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.
From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.
The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have
.
Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.
So the compound is ethyl propionate
Answer: 12033 kJ of heat produced per kg of formed during the combustion of benzene
Explanation:
The balanced chemical equation for combustion of benzene is :
= -6278 kJ
Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and for the reaction comes out to be negative.
(1kg=1000g)
According to stoichiometry :
12 moles of on combustion produce heat = 6278 kJ
Thus 23 mole of on combustion produce heat =
Thus 12033 kJ of heat produced per kg of formed during the combustion of benzene