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3 years ago

With all the coefficient set to 1, how can you tell that the equation is not balanced?

Chemistry

1 answer:

murzikaleks [220]3 years ago

7 0

Answer:

Well for any equation if all the coefficients are set to 1, this might result in unequal numbers of atoms of the same element on both sides

Explanation:

For example:

$A+B---->B_{2} + A_{2}$ (for this equation all the coefficient (the number before element) are 1 but you can clearly see it is not balanced because one side has 1 A atom and other side has 2 B atoms....therefore we need to balance em.

$2A+2B-----> A_{2} + B_{2}$ Here both atoms are balanced.

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What is the use of a pedigree chart? Please do not answer wat a perigee chart is!.

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Pedigree charts are used to see traits that are present in families or individuals. For example, it can be used see if certain diseases are running through someone's family and if that individual will inherit the disease.

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3 years ago

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The reaction shown below has a positive enthalpy change and a negative entropy change. 2C (s) + 2H2 (g) yields C2H4 (g) Which of

Drupady [299]

Answer is: <span>The reaction will not be spontaneous at any temperature.

</span>

<span>Gibbs free energy (G) determines if reaction will proceed spontaneously.
ΔG = ΔH - T·ΔS.
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ΔH - changes in enthalpy.
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T is temperature in Kelvins.
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3 years ago

A sample of an ionic compound NaA, where A- is the anion of a

vitfil [10]

Answer:

a) Kb = 10^-9

b) pH = 3.02

Explanation:

a) pH 5.0 titration with a 100 mL sample containing 500 mL of 0.10 M HCl, or 0.05 moles of HCl. Therefore we have the following:

[NaA] and [A-] = 0.05/0.6 = 0.083 M

Kb = Kw/Ka = 10^-14/[H+] = 10^-14/10^-5 = 10^-9

b) For the stoichiometric point in the titration, 0.100 moles of NaA have to be found in a 1.1L solution, and this is equal to:

[A-] = [H+] = (0.1 L)*(1 M)/1.1 L = 0.091 M

pKb = 10^-9

Ka = 10^-5

HA = H+ + A-

Ka = 10^-5 = ([H+]*[A-])/[HA] = [H+]^2/(0.091 - [H+])

[H+]^2 + 10^5 * [H+] - 10^-5 * 0.091 = 0

Clearing [H+]:

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6 0

3 years ago

600.0 mL of air is at 20.0 c what is the volume at 60.0

pogonyaev

682mL

Explanation:

Given parameters:

Initial volume of air = 600mL

Initial temperature = 20°C

Final temperature = 60°C

Unknown:

Final volume = ?

Solution:

To solve this problem, we apply Charles's law';

Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "

Mathematically;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

V₁ is the initial volume of air

T₁ is the initial temperature of air

V₂ is the final volume of air

T₂ is the final temperature of air

To proceed in solving this problem, we need to convert the given temperature to Kelvin;

T K = 273 + T°C

T₁ = 273 + 20 = 293K

T₂ = 273 + 60 = 333K

now input the parameters;

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V₂ = 682mL

learn more:

Gas laws brainly.com/question/2438000

#learnwithBrainly

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