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1 year ago

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When sulfate (SO42-) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is?

1 answer:

o-na [289]1 year ago

3 0

When sulfate (SO₄²⁻) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is hydrogen sulfide (H₂S).

How sulfate acts as electon acceptor and electron donor?

Sulfate (SO₄²⁻) is used as the electron acceptor in sulfate reduction, which results in the production of hydrogen sulfide (H2S) as a metabolic byproduct.
Many Gram negative bacteria identified in the -Proteobacteria use sulfate reduction, which is a rather energy-poor process.
Gram-positive organisms connected to Desulfotomaculum or the archaeon Archaeoglobus also utilise it.
Electron donors are needed for sulfate reduction, such as hydrogen gas or the carbon molecules lactate and pyruvate (organotrophic reducers) (lithotrophic reducers).

Learn more about the Electron transport chain with the help of the given link:

brainly.com/question/24372542

#SPJ4

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Any element can always be identified by its:

Alborosie

Explanation:

atomic mass

Really...i think it can also be atomic number..

3 0

3 years ago

An element has an atomic mass of 69.66 amu. It has two

marin [14]

Answer: 63.26%

Explanation:

If we let the abundance of the first isotope be x, then:

$69.66=(68.9255)(x)+(70.9247)(1-x)\\69.66=68.9255x+70.9247-70.9247x\\-1.2647=-1.9992x\\x=\frac{-1.2647}{-1.9992} \approx 0.6326$

Which is equal to <u>63.26%</u>

7 0

1 year ago

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Mamont248 [21]

Answer:

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6 0

2 years ago

A solution of copper sulfate (CuSO4) produced by bioleaching has a concentration of 0.319 g/dm3 Relative atomic masses (Ar): Cu

Tanya [424]

moles Cu produced : 0.002

<h3>Further explanation</h3>

Concentration of copper sulfate (CuSO₄) : 0.319 g/dm³

MW CuSO₄ :

$\tt =63.5+32+4\times 16=159.5~g/mol$

mol CuSO₄ /dm³ :

$\tt \dfrac{0.319}{159.5}=0.002$

CuSO₄⇒Cu²⁺ + SO₄²⁻

mol Cu : mol CuSO₄ = 1 : 1 , so mol Cu²⁺=0.002

6 0

2 years ago

A certain hydrocarbon has a molecular formula of C9H16. Which of the following is not a structural possibility for this hydrocar

snow_tiger [21]

Answer: Option (d) is the correct answer.

Explanation:

It is given that molecular formula is $C_{9}H_{16}$ . Now, we will calculate the degree of unsaturation as follows.

Degree of unsaturation = $C_{n} - \frac{\text{monovalent}}{2} + \frac{\text{trivalent}}{2} + 1$

= $9 - \frac{16}{2} + 1$

= 9 - 8 + 1

= 2

As the degree of unsaturation comes out to be 2. It means that this compound will contain one ring and one double bond.

Yes, this compound could be an alkyne as for alkyne D.B.E = 2.

But this compound cannot be a cycloalkane because for a cycloalkane D.B.E = 1 which is due to the ring only.

Thus, we can conclude that it is a cycloalkane is not a structural possibility for this hydrocarbon.

6 0

3 years ago