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Inga [223]
2 years ago
9

When sulfate (SO42-) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is?

Chemistry
1 answer:
o-na [289]2 years ago
3 0

When sulfate (SO₄²⁻) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is hydrogen sulfide (H₂S).

How sulfate acts as electon acceptor and electron donor?

  • Sulfate (SO₄²⁻) is used as the electron acceptor in sulfate reduction, which results in the production of hydrogen sulfide (H2S) as a metabolic byproduct.
  • Many Gram negative bacteria identified in the -Proteobacteria use sulfate reduction, which is a rather energy-poor process.
  • Gram-positive organisms connected to Desulfotomaculum or the archaeon Archaeoglobus also utilise it.
  • Electron donors are needed for sulfate reduction, such as hydrogen gas or the carbon molecules lactate and pyruvate (organotrophic reducers) (lithotrophic reducers).

Learn more about the Electron transport chain with the help of the given link:

brainly.com/question/24372542

#SPJ4

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3 years ago
What is 57.048 rounded to three significant figures?
AnnyKZ [126]
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4 0
3 years ago
PLEASE HELP
neonofarm [45]

Answer:

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

               = 342 g

2.- Convert the mass of sucrose to moles

                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

Molarity = 0.10

5 0
3 years ago
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Snowcat [4.5K]
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