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3 years ago

Looking at the map, what ideas do you have about why the trash is "trapped" in this location

Chemistry

1 answer:

grandymaker [24]3 years ago

7 0

Answer:

Due to the circulation of the wind and water the trash will continue to go around in a circle thus causing it to be trapped there.

You might be interested in

Which type of electromagnetic wave has less energy than a microwave?

polet [3.4K]

Radio waves.

From lowest to highest it is radio wave, microwave, infrared, visible light, ultraviolet, x ray, and then gamma.

7 0

2 years ago

Consider the group 1A elements sodium (period 3), potassium (period 4), and rubidium (period 5). What would you predict about th

enyata [817]

The correct answer is Na > K > Rb.

The order predicted would be ionization energy of sodium is greater than the ionization energy of potassium, which is greater than the ionization energy of rubidium.

The ionization energy refers to energy, which has to be supplemented to a gaseous atom in order to withdraw an electron and produce a positive ion. The ionization energy decreases in going down a group. The cause of the decline of the ionization energy down a group is that as one moves down a group, the size of the atom increases that signifies that the valence electrons get further away from the nucleus, and thus, less energy is required to withdraw the electrons.

4 0

3 years ago

Read 2 more answers

What is the mole ratio of <br> N2 + 3H2 Right arrow. 2NH3

Oksana_A [137]

Answer:mole ratio between N2 and 2NH3 is 1:2while mole ratio between H2 and 2NH3 is 3:2

Explanation: 1 mole of N2 is required to produce 2 moles of NH3 while 3moles of H2 is required to produce 2 moles of NH3

8 0

4 years ago

How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos

Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of $H_3PO_4$ = 54.219 g

Number of atoms of $Mg$ = $7.179\times 10^{23}$

Molar mass of $H_3PO_4$ = 98 g/mol

First we have to calculate the moles of $H_3PO_4$ and $Mg$ .

$\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}$

$\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol$

and,

$\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2$

From the balanced reaction we conclude that

As, 3 mole of $Mg$ react with 2 mole of $H_3PO_4$

So, 0.553 moles of $Mg$ react with $\frac{2}{3}\times 0.553=0.369$ moles of $H_3PO_4$

From this we conclude that, $H_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2$

From the reaction, we conclude that

As, 3 mole of $Mg$ react to give 3 mole of $H_2$

So, 0.553 mole of $Mg$ react to give 0.553 mole of $H_2$

Now we have to calculate the volume of $H_2$ gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies $0.553\times 22.4=12.4L$ volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0

3 years ago

Select the most likely product for this reaction: upper a g upper n upper o subscript 3 (a q) plus upper n a upper o upper h (a

Mamont248 [21]

One of the most likely products for the reaction would be $Ag_2O$

<h3>Chemical reactions</h3>

The reaction between $AgNO_3$ and $NaOH$ yields 3 products which are $Ag_2O$ (a precipitate), $NaNO_3$ , and $H_2O$ as shown by the equation below:

$2 AgNO_3 + 2 NaOH --- > Ag_2O + 2 NaNO_3 + H_2O$

One of the products precipitates out of the solution to give the reaction a precipitation reaction look.

More on precipitation reaction can be found here: brainly.com/question/24158764

#SPJ4

5 0

2 years ago

Read 2 more answers