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Taya2010 [7]
1 year ago
13

Substance Density (grams/cm3)Chloroform - 1.5Ebony wood - 1.2Mahogany wood - 0.85Oil - 0.9Water - 1.024.A block of ebony wood is

placed in the container with the water, chloroform, and oil. On which layer does the ebony wood float?Select one:a. Chloroform.b. Oil.c. Water.d. None; it will sink.
Chemistry
1 answer:
marissa [1.9K]1 year ago
6 0

Determining if an object will float or sink is based on the density of the object and also the density of the solution, the lower the density, more likely the object is to float, and if the density is higher, therefore the object is heavier and it will sink. In our question we have ebony wood with a density of 1.2, the only possible layer that this material can float is on Chloroform, that has a higher density, therefore the answer is letter A

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Calculate the value of the equilibrium constant, Kc , for the equilibrium shown below, if 0.124 moles of NO, 0.0240 mole of H2,
sdas [7]

the reaction is

2NO(g) + 2H2(g) <—> N2(g) + 2H2O (g)

Kc = [N2] [ H2O]^2 / [NO]^2 [ H2]^2

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4 0
3 years ago
The first-order rate constant for the reaction of methyl chloride (CH3Cl) with water to produce methanol (CH3OH) and hydrochlori
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Answer:

K(48.5°C) = 1.017 E-8 s-1

Explanation:

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at T1 = 25°C (298 K) ⇒ K1 = 3.32 E-10 s-1

at T2 = 48.5°C (321.5 K) ⇒ K2 = ?

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∴ A: frecuency factor

∴ R = 8.314 E-3 KJ/K.mol

⇒ Ln K1 = Ln(A) - [Ea/R)*(1/T1)]..........(1)

⇒ Ln K2 = Ln(A) - [(Ea/R)*(1/T2)].............(2)

(1)/(2):

⇒ Ln (K1/K2) = (Ea/R)* (1/T2-1/T1)

⇒ Ln (K1/K2) = (116 KJ/mol/8.3134 E-3 KJ/K.mol)*(1/321.5 K - 1/298 K)

⇒ Ln (K1/K2) = (13952.37 K)*(- 2.453 E-4 K-1)

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⇒ K2 = (3.32 E-10 s-1)/0.0326

⇒ K2 = 1.017 E-8 s-1

7 0
3 years ago
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