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tekilochka [14]
2 years ago
5

A teacher told a learner to react benzene (CH) with chlorine (Cl₂) to

Physics
1 answer:
kolezko [41]2 years ago
3 0

The minimum quantity of benzene, C₆H₆ needed for the reaction is 106.67 g

<h3>How to determine the theoretical yield of chlorobenzene, C₆H₅Cl</h3>

From the question given, the following data were obtained

  • Actual yield = 100 g
  • Percentage yield = 65%
  • Theoretical yield =?

Percentage yield = (Actual / Theoretical) × 100

65% = 100 / Theoretical

0.65 = Actual / Theoretical

Cross multiply

0.65 × Theoretical = 100

Divide both sides by 0.65

Theoretical = 100 / 0.65

Theoretical yield = 153.85 g

<h3>How to determine the mass of benzene, C₆H₆ needed</h3>

Balanced equation

C₆H₆ + Cl₂ → C₆H₅Cl + HCl

Molar mass of C₆H₆ = 78 g/mol

Mass of C₆H₆ from the balanced equation = 1 × 78 = 78 g

Molar mass of C₆H₅Cl = 112.5 g

Mass of C₆H₅Cl from the balanced equation = 1 × 112.5 = 112.5 g

SUMMARY

From the balanced equation above,

112.5 g of C₆H₅Cl were obtained from 78 g of C₆H₆

Therefore,

153.85 g of C₆H₅Cl will be produced from = (153.85 × 78) / 112.5 = 106.67 g of C₆H₆

Thus, the minimum amount of benzene, C₆H₆ needed for the reaction is 106.67 g

Learn more about stoichiometry:

brainly.com/question/16735180

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Gases, just like liquids are made of particles which can be further classified as atoms or molecules,
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Answer:

True

Explanation:

Solids, Liquids, and Gases are all make up of <u><em>atoms and molecules. </em></u>

8 0
3 years ago
The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
pochemuha

Since g is constant,  the force the escaping gas exerts on the rocket will be 10.4 N

<h3>What is Escape Velocity ?</h3>

This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.

Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.

To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters

  • Mass (m) of the rocket 0.25 Kg
  • Initial velocity u = 15 m/s
  • Final Velocity v = 40 m/s
  • Time t = 0.6s
  • Gravitational field intensity g = 9.8N/kg

The force the gas exerts of the rocket = The force on the rocket

The rate change in momentum of the rocket = force applied

F = ma

F = m(v - u)/t

F = 0.25 x (40 - 15)/0.6

F = 0.25 x 41.667

F = 10.42 N

Since g is constant,  the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.

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7 0
2 years ago
A 20,000 kg railroad car is traveling at 5 m/s when it collides and couples with a second, identical car at rest. What is the re
PilotLPTM [1.2K]
Ok I don’t know the answer I’m in 5th grade but 2431 is wrong
7 0
3 years ago
Please help me find this answer
djyliett [7]

Answer:

155/62 = 2.5

Mass/Volume = Density

Density= 2.5

Explanation:

5 0
2 years ago
Read 2 more answers
Rita throws a ball straight up into the air and catches it at the
Kaylis [27]

(1) The potential energy at the top of the ball’s motion is 18 J.

(3) The kinetic energy increases as the potential energy decreases.

(4) The kinetic energy decreases as the potential energy increases.

(5) The total mechanical energy of the ball stays constant.

Explanation:

The total mechanical energy of the ball is equal to the sum of its kinetic energy (K, energy due to the motion) and its potential energy (U, energy due to the height of the ball). Mathematically:

E=K+U

In absence of friction, the mechanical energy of the ball is conserved, so in this case, it is always equal to 18 J. Let's now use this information to analyze each of the given statements:

(1) The potential energy at the top of the ball’s motion is 18 J.  --> TRUE. In fact, at the top, the ball's speed becomes zero, so its kinetic energy is zero: K = 0. This means that all the mechanical energy of the ball is potential energy, therefore

E = U = 18 J

(2) The kinetic energy is less when the ball is thrown than when it is caught.   --> FALSE. As we said, in absence of friction, the mechanical energy is conserved, therefore it always remains equal to 18 J.

(3) The kinetic energy increases as the potential energy decreases.  --> TRUE. As we said, the sum of potential+kinetic energy remains constant:

E = K + U = 18 J

therefore, when the potential energy decreases, the kinetic energy increases.

(4)The kinetic energy decreases as the potential energy increases.  --> TRUE. For the same reason described in (3).

(5)The total mechanical energy of the ball stays constant.  --> TRUE. As we said at the beginning, the total mechanical energy is constant.

(6) The mechanical energy decreases as the ball moves up and increases as the ball comes down. --> FALSE. As we said, the mechanical energy remains constant, so it cannot change.

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6 0
3 years ago
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