Answer:
1. True WA > WB > WC
Explanation:
In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.
A) Work is the product of force by distance and the cosine of the angle between them
WA = W h cos 0
WA = mg h
B) On a ramp without rubbing
Sin30 = h / L
L = h / sin 30
WB = F d cos θ
WB = F L cos 30
WB = mf (h / sin30) cos 30
WB = mg h ctan 30
C) Ramp with rubbing
W sin 30 - fr = ma
N- Wcos30 = 0
W sin 30 - μ W cos 30 = ma
F = W (sin30 - μ cos30)
WC = mg (sin30 - μ cos30) h / sin30
Wc = mg (1 - μ ctan30) h
When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum
Let's review the claims
1. True The work of gravity is the greatest and the work where there is friction is the least
2 False. The job where there is friction is the least
3 False work with rubbing is the least
4 False work with rubbing is the least
Answer:2.47
Explanation:
So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!
Answer:
B. Solids, liquids, and gases.
Explanation:
I have no explanation.
Answer:
5.9 x 10⁻⁷m
Explanation:
Given parameters:
Frequency = 5.085 x 10¹⁴Hz
Speed of light = 3.0 x 10⁸m/s
Unknown:
Wavelength of the orange light = ?
Solution:
The wavelength can be derived using the expression below;
wavelength =
v is the speed of light
f is the frequency
wavelength =
= 5.9 x 10⁻⁷m
Answer:
A) 7.0 m/s²
Explanation:
Acceleration is found by using the formula:
This means the change in time divided by the time interval will give us the car's acceleration.
Since the car starts from rest, its initial velocity is 0 m/s. Its final velocity is 35 m/s. The time interval for the car to go from 0 to 35 m/s is 5.0 seconds.
Substitute the final and initial velocity into the formula.
- a = (35 - 0)/5
- a = 35/5
- a = 7
The acceleration of the car is A) 7.0 m/s².